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stiv31 [10]
3 years ago
15

Plz help

Physics
2 answers:
musickatia [10]3 years ago
7 0

The water. Take the specific heat of steel, estimate the volume of the nail, you know the volume of the water, which has a specific heat of one. Or be obvious. If you dropped a red hot nail into a liter of cold water, what would happen?

Answer:

Water

Goryan [66]3 years ago
5 0

☆One litre boiling water has more amount of heat because it has much more greater mass than iron nail

I am not sure if its wrong,sorry

but here is the iron nail explanation also

☆A red hot nail has more amount of heat because the density of iron is more than that of water

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What is the surface temperature of a star that has a peak wavelength of 290 nm?
Maksim231197 [3]
We need to use Wien's Law

Wavelength = 0.0028976 [m.K] / T

This establishes a relation between the wavelength and temperature of a black body (any body that absorbs radiation, such as the stars)

T = 0.0028976 [m.K]/290 E-9[m]  = 9991.724 K
5 0
3 years ago
Christian made some pancakes she's so 3/5 of them in the morning and 1/4 of the remainder in the afternoon is she had 300 pancak
DiKsa [7]

Christian made 1000 pancakes.

Explanation:

Let us represent the total amount of Pancake made by Christian as = K

    From the problem;

 Christian ate \frac{3}{5} of the pancake in the morning =  \frac{3}{5}  * K =  \frac{3}{5} K

We know that Christian cannot eat her pancake and at the same time have it, the  remaining pancake will then be:

        total amount of cake - fraction eaten

Remainder = K -  \frac{3}{5} K=  \frac{2}{5} K

   

In the afternoon, we know that she ate 1/4 of the remaining cake:

        \frac{1}{5} K*  \frac{2}{5} K = \frac{1}{10} K

 The remaining cake in the afternoon will be:

    Total amount of cake remaining from morning - amount eaten in the afternoon

    =    \frac{2}{5} K -  \frac{1}{10} K

    =    \frac{3}{10} K

The fraction of the cake remaining in the afternoon is  \frac{3}{10} K

Since she had 300cakes left in the afternoon, then :

            \frac{3}{10} K= 300

                    K = 1000 pancakes

Therefore Christian made 1000 pancakes.

learn more:

Fractions brainly.com/question/1648978

#learnwithBrainly

4 0
3 years ago
A proton is confined to a space 1 fm wide (about the size of an atomic nucleus). What's the minimum uncertainty in its velocity?
Daniel [21]

Answer:

Minimum uncertainty in velocity of a proton,\Delta v\ge 3.15\times 10^7\ m/s      

Explanation:

It is given that,

A proton is confined to a space 1 fm wide, \Delta x=10^{-15}\ m

We need to find the minimum uncertainty in its velocity. We know that the Heisenberg Uncertainty principle gives the uncertainty between position and the momentum such that,

\Delta p.\Delta x\ge \dfrac{h}{4\pi}

Since, p = mv

\Delta (mv).\Delta x\ge \dfrac{h}{4\pi}

m \Delta v.\Delta x\ge \dfrac{h}{4\pi}

\Delta v\ge \dfrac{h}{4\pi m\Delta x}

\Delta v\ge \dfrac{6.63\times 10^{-34}}{4\pi \times 1.67\times 10^{-27}\times 10^{-15}}

\Delta v\ge 3.15\times 10^7\ m/s

So, the minimum uncertainty in its velocity is greater than 3.15\times 10^7\ m/s. Hence, this is the required solution.

3 0
3 years ago
A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0
3 years ago
List several examples of applied force, normal force, and friction that you’ve observed in your life.
grandymaker [24]

applied forces would be push for example.

normal forces would seem to be a force such as gravity.

friction for example when you try to slide on carpet but the fabric or whatever its made of stops you.

3 0
3 years ago
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