Answer: The correct answer is The aplastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.
Explanation: The formula for Gravitational potential energy is= mgh where
m= mass
g= 9.8
h= height
On the other hand the formula for elastic potential energy is (1/2)KX^2
Where K is the spring. By changing the values of H and X, we will see elastic potential energy will remain more.
Answer: 0.023 liters
Explanation:
Given that,
Original volume of gas (V1) = 25mL
[convert 25mL to liters
If 1000ml = 1L
25ml = 25/1000 = 0.025L]
Original temperature of gas (T1) = 22°C
[Convert 22°C to Kelvin by adding 273
22°C + 273 = 295K]
New volume of gas (V2) = ?
New temperature of gas (T2) = 0°C
[Convert 0°C to Kelvin by adding 273
0°C + 273 = 273K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.025L/295K = V2/273K
To get the value of V2, cross multiply
0.025L x 273K = 295K x V2
6.825L•K = 295K•V2
Divide both sides by 295K
6.825L•K/295K = 295K•V2/295K
0.023 L = V2
Thus, the new volume of the gas will be 0.023 litres
Answer:
Ag⁺(aq) + I⁻(aq) → AgI(s)
Explanation:
Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.
In the reaction:
AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).
The ionic equation is:
Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).
Now, listing only the species that are participating in the reaction:
<h3>Ag⁺(aq) + I⁻(aq) → AgI(s)</h3>
Answer:
Rhombic sulphur and monoclinic sulphur.
The given chemical reaction is:
Δ
∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine = 
= 1.20 mol 
Heat change when 1.20 mol chlorine reacts
= 
