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mezya [45]
4 years ago
10

Think about the different rules that describe how gases behave. To do this, refer to what you have learned about the two princip

les concerning pressure and the three gas laws. Summarize what each of these five rules state about the behavior of gases. Then, give an example of a practical application for each one. (Pressure)
Chemistry
1 answer:
VMariaS [17]4 years ago
4 0

Answer:

Described down below.

Explanation:

Hello,

- Boyle's law: correlation between pressure and volume (assuming temperature and amount of gas remain constant). One common use of Boyle’s law is to predict the new volume of a gas when the pressure is changed (at constant temperature), or vice versa

- Charles' law: correlation between temperature and volume (assuming pressure and amount of gas remain constant). It is used to prove that the absolute 0 unattainable (T=0K).

- Avogadro's law: correlation between amount of gas and volume (assuming temperature  and pressure p remain constant). As an example, since we can blow up a basketball, we are adding more gas molecules into it. The more gaseous molecules, the greater the volume.

- Dalton's law: correlation that states that for a mixture of gases in a container, the total pressure exerted is the addition among each pressure that each gas would exert if it were alone. It is useful to analyze the effects of which partial pressure might have on scuba divers. While the total gas pressure increases as a diver increases their descent, the partial pressure of each gas involved increases as well which might cause harm to the diver’s body if proper actions are not carried out.

- Gay-Lussac's law: it states that when the temperature of a sample of gas in a rigid container is increased, the pressure of the gas increases as well. An interesting example is shown when gun pin strikes, because it ignites the gun powder and this increases the temperature which in turn increases the pressure and bullet is fired from the gun.

Best regards.

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Why are the bacterial endospores placed on the paper strip and not directly in the fermentation broth?
Artyom0805 [142]
The bacterial endospores are microorganisms formed due to nutrient deprivation. These are placed first on a paper strip and not directly in the fermentation broth because these microorganisms are very resistance, thus, they need to adjust to the environment first before being acclimated to it. 
6 0
4 years ago
Which of the following shows a valid combustion reaction?
marta [7]

Answer:   C2H4 + 3O2 → 2CO2 + 2H2O

Explanation:

2Al + 2O2 → 2AlO + O2            Not Balanced Properly:  2Al + O2 = 2AlO  

C2H4 + 3O2 → 2CO2 + 2H2O  Looks Good

2CH4 + O2 → 2CO + 4H2          Not Correct:  CO should be CO2

Ca + O2 → CaOH                        Not Balanced and No source for the H

3 0
2 years ago
Read 2 more answers
PLeaseee ITS Timedddd + BrainlIESTT
uysha [10]

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced chemical equation of this chemical reaction is as follows:

4Al + 3O2 --> 2Al2O3

Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

First, we need to convert the mass of aluminum to moles using the formula;

mole = mass/molar mass

Molar mass of Al = 27g/mol

mole = 6.50/27

= 0.241mol of Al.

Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

= 54 + 48

= 102g/mol

mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

5 0
3 years ago
Titration Volume & Concentration
polet [3.4K]

Answer:

18,1 mL of a 0,304M HCl solution.

Explanation:

The neutralization reaction of Ba(OH)₂ with HCl is:

2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O

The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:

0,0171L*\frac{0,161moles}{L} = 2,7531x10⁻³moles of Ba(OH)₂

By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:

2,7531x10^{-3}molBa(OH)_{2}*\frac{2molHCl}{1molBa(OH)_{2}} = 5,5062x10⁻³moles of HCl.

The volume of a 0,304M HCl solution for a complete neutralization is:

5,5062x10^{-3}molHCl*\frac{1L}{0,304mol} = 0,0181L≡18,1mL

I hope it helps!

4 0
3 years ago
A gas occupies 10.2 liters at 0.60 atm. What is the pressure if the volume becomes 3.0 L?
Arturiano [62]
P1V1 = P2V2
P1 = 0.60 atm
V1 = 10.2 L
P2 = ?
V2 = 3.0 L

Solve for P2 —> P2 = P1V1/V2 = (0.60 atm)(10.2 L) / (3.0 L) = 2.04 atm
3 0
3 years ago
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