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valentina_108 [34]
3 years ago
14

A rock has a mass of 12.947g. A graduated cylinder has 41.3 mL of water. The rock is placed in the water, and now the volume rea

ds 46.2mL. What is the density of the rock?
Chemistry
1 answer:
velikii [3]3 years ago
5 0

Answer:

<h2>Density = 2.64 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of rock = 12.947 g

Volume of rock = final volume of water - initial volume of water

Volume = 46.2 mL - 41.3 mL = 4.9 mL

Substitute the values into the the above formula and solve for the density

That's

Density =  \frac{12.947}{4.9}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2.642244

We have the final answer as

<h3>Density = 2.64 g/mL</h3>

Hope this helps you

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An electrochemical cell is constructed such that on one side a pure lead electrode is in contact with a solution containing Pb2+
Ugo [173]

Answer:

-490.7 K

Explanation:

Given:

[Ni^2+]= 0.4 M

[Pb^2+]=0.002 M

∆V= -0.012 V

VNi= -0.250V

VPb= -0.126V

F= 96500 C

R= 8.314 JK-1 mol-1

n= 2

From

T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]

T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]

T= 23213.856(0.112/(-5.298))

T= -490.7 K

4 0
3 years ago
1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage
Jet001 [13]

Answer:

V_{p} = 15 V

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}

Making Vp the subject of formula;

V_{p} = \frac{N_{p}}{N_{s}} * V_{s}

Substituting into the equation, we have;

V_{p} = \frac{1}{8} * 120

V_{p} = \frac{120}{8}

V_{p} = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0
3 years ago
Which element would most likely have chemical properties similar to that of fluorine (F)?
vredina [299]
The question is asking to state the element would most likely have chemical properties similar to that of fluorine and base on my research and further investigation, I would say that it would be Bromine. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications 
8 0
4 years ago
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N__________ is the study of atoms.
AlekseyPX
I think the answer might be nuclear physics
3 0
4 years ago
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Which one of the following is not a valid expression for the rate of the reaction below? 4NH3 + 7O2 → 4NO2 + 6H2O Which one of t
Veseljchak [2.6K]

Answer : All of the above are valid expressions of the reaction rate.

Explanation :

The given rate of reaction is,

4NH_3+7O_2\rightarrow 4NO_2+6H_2O

The expression for rate of reaction for the reactant :

\text{Rate of disappearance of }NH_3=-\frac{1}{4}\times \frac{d[NH_3]}{dt}

\text{Rate of disappearance of }O_2=-\frac{1}{7}\times \frac{d[O_2]}{dt}

The expression for rate of reaction for the product :

\text{Rate of formation of }NO_2=+\frac{1}{4}\times \frac{d[NO_2]}{dt}

\text{Rate of formation of }H_2O=+\frac{1}{6}\times \frac{d[H_2O]}{dt}

From this we conclude that, all the options are correct.

3 0
3 years ago
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