Answer:
Here's what I get
Explanation:
1. In dilute NaOH
(a) Molecular equation
AlCl₃(aq) + 3NaOH(aq) ⟶ Al(OH)₃(s) + 3NaCl(aq)
(b) Ionic equation
You write the molecular formulas for solids, and you write the soluble ionic substances as ions.
Al³⁺(aq) + 3Cl⁻(aq) + 3Na⁺(aq) + 3OH⁻(aq) ⟶ Al(OH)₃(s) + 3Na⁺(aq) + 3Cl⁻(aq)
(c) Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
Al³⁺(aq) + <u>3Cl⁻(aq)</u> + <u>3Na⁺(aq</u>) + 3OH⁻(aq) ⟶ Al(OH)₃(s) + <u>3Na⁺(aq)</u> + <u>3Cl⁻(aq)
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The net ionic equation is
Al³⁺(aq) + 3OH⁻(aq) ⟶ Al(OH)₃(s)
2. In excess NaOH
The aluminium hydroxide reacts with excess hydroxide to form sodium tetrahydroxoaluminate(III).
(a) Molecular equation
AlCl₃(aq) + 4NaOH(aq) ⟶ NaAl(OH)₄(aq) + 3NaCl(aq)
(b) Ionic equation
Al³⁺(aq) + 3Cl⁻(aq) + 4Na⁺(aq) + 4OH⁻(aq) ⟶ Na⁺Al(OH)₄⁻(aq) + 3Na⁺(aq) + 3Cl⁻(aq)
(c) Net ionic equation
Al³⁺(aq) + 4OH⁻(aq) ⟶ Al(OH)₄⁻(aq)
Hey there!
Your answer is B. MgCl.
This is because this isn't an actual existing compound.
Water (H₂O) and magnesium chloride (MgCl₂) are both real compounds, but the number of electrons does not line up to make MgCl possible.
Hope this helps!
Answer:
True statements are 2, 4, 5
Explanation:
They can be broken down by chemical means because we need to break chemical bonds between two (or more) atoms.
They are pure substance because one can't separate them by physical means.
When one separate compounds on two (or more) substances, there are two (or more) different species and they all act differently.
This is probably wrong but i think the answer is 1,979,381.44