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Alexxx [7]
3 years ago
10

How many moles are present in 16.9 g of Al2O3?

Chemistry
2 answers:
daser333 [38]3 years ago
7 0

0.166 mol are present in 16.9 g of Al2O3.

Dahasolnce [82]3 years ago
4 0
<span>The number of moles in Al2O3 is .16575 moles</span>
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Answer is C:Wax Or B:Heat
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Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 1
Drupady [299]

Answer :  The value of second ionization energy of Ca is 1010 kJ.

Explanation :  

The formation of calcium oxide is,

Ca(s)+\frac{1}{2}O_2(g)\overset{\Delta H_f}\rightarrow CaO(s)

\Delta H_f^o = enthalpy of formation of calcium oxide = -635 kJ

The steps involved in the born-Haber cycle for the formation of CaO:

(1) Conversion of solid calcium into gaseous calcium atoms.

Ca(s)\overset{\Delta H_s}\rightarrow Ca(g)

\Delta H_s = sublimation energy of calcium = 193 kJ

(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

Ca(g)\overset{\Delta H_I_1}\rightarrow Ca^{+1}(g)

\Delta H_I_1 = first ionization energy of calcium = 590 kJ

(3) Conversion of gaseous calcium ion into gaseous calcium ions.

Ca^{+1}(g)\overset{\Delta H_I_2}\rightarrow Ca^{+2}(g)

\Delta H_I_2 = second ionization energy of calcium = ?

(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.

O_2(g)\overset{\Delta H_D}\rightarrow OI(g)

\frac{1}{2}O_2(g)\overset{\Delta H_D}\rightarrow O(g)

\Delta H_D = dissociation energy of oxygen = \frac{498}{2}=249kJ

(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

O(g)\overset{\Delta H_E_1}\rightarrow O^-(g)

\Delta H_E_1 = first electron affinity energy of oxygen = -141 kJ

(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

O^-(g)\overset{\Delta H_E_2}\rightarrow O^{2-}(g)

\Delta H_E_2 = second electron affinity energy of oxygen = 878 kJ

(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

Ca^{2+}(g)+O^{2-}(g)\overset{\Delta H_L}\rightarrow CaO(s)

\Delta H_L = lattice energy of calcium oxide = -3414 kJ

To calculate the overall energy from the born-Haber cycle, the equation used will be:

\Delta H_f^o=\Delta H_s+\Delta H_I_1+\Delta H_I_2+\Delta H_D+\Delta H_E_1+\Delta H_E_2+\Delta H_L

Now put all the given values in this equation, we get:

-635kJ=193kJ+590kJ+\Delta H_I_2+249kJ+(-141kJ)+878kJ+(-3414kJ)

\Delta H_I_2=1010kJ

Therefore, the value of second ionization energy of Ca is 1010 kJ.

6 0
3 years ago
a. How can one tell if a chemical reaction is balanced? (.5 point) b. What information does a complete ionic equation give that
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Answer:

I think it's C

Explanation:

i think its c b3cause when you guess c always feels right

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2 years ago
How many molecules are in 71.3 moles of H2O
Svetradugi [14.3K]
H2O molar mass= 18.02
Use Avogadro’s constant to convert moles into particles.
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There are 429.229 molecules in 71.3 moles of H2O
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When magnesium reacts with chlorine, the chlorine atom gain electrons. what happens to chlorine in this reaction?
Mrrafil [7]

Answer:

D

Explanation:

Reduction refers to gain in electrons. Hence it is D

Oxidation occurs when the element loses electrons. Hence A is wrong

7 0
3 years ago
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