<u><em>Answer</em></u>
A) 1,347.5 Joules
B) 22.49 m/s
<u><em>Explanation</em></u>
<u>Part A</u>
The work done by the gravity is known as potential energy.
It is given by;
P.E = mgh
Where m is mass, g is acceleration due to gravity and h is the vertical height.
P.E = 5.5 × 9.8 ×25
= 1,347.5 Joules.
<u>Part B</u>
Using the Newton's third Law of motion,
V² = U² +2as
Where v is final velocity, u is the initial velocity, and s is the displacement of the stone.
V² = 4² + (2×9.8×25)
= 16 + 490
= 506
V = √506
= 22.49 m/s
Answer:
The P site
Explanation:
After the formation of peptide linkage, the trna of P site becomes free, more to the E site and then slip away. The A site trna has dipeptide instead of a single aminoacid.
In the prescence of translocase and energy from GTP, the ribosome move in such a way the peptidyl bearing trna of A site come to lie with P sit. This exposes next codon to A site. A new aminoacid trna complex reaches the fresh codon exposed at A site.
Answer:
Transduction.
Explanation:
Transduction is actually a process which involves the conversion of energies or messages from one kind to another. So in this case the transfer of light energy received by the eyes into the message for the brain is also called as transduction.
Students should be sure to put on their goggles during chemical test.
Students should be sure to wear their hand gloves during chemical test.
Answer:
1.78 J
Explanation:
Find the spring coefficient using Hooke's law:
F = k Δx
23 N = k (0.20 m − 0.14 m)
k = 383.33 N/m
The work is the change in energy:
W = PE₂ − PE₁
W = ½ kx₂² − ½ kx₁²
W = ½ k (x₂² − x₁²)
W = ½ (383.33 N/m) ((0.17 m)² − (0.14 m)²)
W = 1.78 J