you can determine it by the wavelenght and the period of the wave and the frequencey
Answer:
Solution
λ=v/n
Here, v=344 m s−1
n=22 MHz =22×106 Hz
λ=344/22×106=15.64×10−6m=15.64μm.
15.0 N
Explanation:
see pic
The distance decreases as the time increases
