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ra1l [238]
3 years ago
12

The difference between the speed of sound n air at 0°C and the speed of sound in air at 20°c is that... A. Cooler air molecules

move more slowly and respond less readily to the energy of a sound wave. B. Cooler air molecules move more quickly and respond less readily to the energy of a sound wave. C. Cooler air molecules do not move and respond less readily to the energy of a sound wave. D. Cooler air molecules move more randomly and respond less readily to the energy of a sound wave.
Physics
2 answers:
sergejj [24]3 years ago
7 0
Heat, like sound, is kinetic energy. Molecules at higher temperatures heave more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly. 

So the answer is A.
KiRa [710]3 years ago
3 0

Answer:

on usatest prep its b

Explanation:

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1

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If a scientist gets unexpected results during the first trial of an experiment,
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A. Repeat the experiment to be sure the results are valid.

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Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What i
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Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

v = \sqrt{\frac{F}{\mu} }

where F = tension force

μ = mass per unit length

Mass per unit length is given as:

μ  = m / l

where m = mass of the string

l = length of the string

This implies that:

v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }

Let us make mass, m, the subject of the formula:

v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}

From the question:

F = 20 N

l = 4.50 m

v = 85 m/s

Therefore:

m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg

5 0
3 years ago
Carbon-14 is used to determine the time an organism was living. The amount of carbon-14 an organism has is constant with the atm
lutik1710 [3]

Answer:

The age of the organism is approximately 11460 years.

Explanation:

The amount of carbon-14 decays exponentially in time and is defined by the following equation:

\frac{n(t)}{n_{o}} = e^{-\frac{t}{\tau} } (1)

Where:

n_{o} - Initial amount of carbon-14.

n(t) - Current amount of carbon-14.

t - Time, measured in years.

\tau - Time constant, measured in years.

Then, we clear the time within the formula:

t = -\tau \cdot \ln \frac{n(t)}{n_{o}} (2)

In addition, time constant can be calculated by means of half-life of carbon-14 (t_{1/2}), measured in years:

\tau = \frac{t_{1/2}}{\ln 2}

If we know that \frac{n(t)}{n_{o}} = 0.25 and t_{1/2} = 5730\,yr, then the age of the organism is:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.25

t \approx 11460.001\,yr

The age of the organism is approximately 11460 years.

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