That depends upon the direction the object moves
The Milky Way galaxy is the one that the sun is a member of, and it contains
our solar system. We're in it, and you can't get much closer than that.
The Milky Way is known to be bigger than your average galaxy, but it's
probably not correct to say that it contains the 'most' stars of any galaxy.
The estimate for the Milky Way is only a few hundred billion stars.
The mass of fuel the engine burn each second to produce a thrust of 7.66×10⁵ N is 2.5×10² kg/s.
<h3 /><h3>What is mass?</h3>
Mass can be defined as the quantity of matter contained in a body. The S.I unit of mass is kilogram(kg)
To calculate the mass the engine burns each seconds, we use the formula below.
Formual:
- M = T/v............. Equation
Where:
- M = Mass per seconds of the rocket
- T = Thrust
- v = Velocity
From the question,
Given:
- T = 7.66×10⁵ N
- v = 3.05×10³ m/s
Substitute these values into equation 1
- M = (7.66×10⁵)/(3.05×10³)
- M = 2.5×10² kg/s
Hence, the mass of fuel burned in each second is 2.5×10² kg/s.
Learn more about mass here: brainly.com/question/25121535
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Answer:
In AM broadcasting, the amplitude of the carrier wave is modulated to encode the original sound. In FM broadcasting, the frequency of the carrier wave is modulated to encode the sound. A radio receiver extracts the original program sound from the modulated radio signal and reproduces the sound in a loudspeaker.
Answer:
The average acceleration of the bearings is 
Explanation:
Given that,
Height = 1.94 m
Bounced height = 1.48 m
Time interval 
Velocity of the ball bearing just before hitting the steel plate
We need to calculate the velocity
Using conservation of energy
Put the value into the formula
Negative as it is directed downwards
After bounce back,
We need to calculate the velocity
Using conservation of energy
Put the value into the formula
We need to calculate the average acceleration of the bearings while they are in contact with the plate
Using formula of acceleration
Put the value into the formula
Hence,The average acceleration of the bearings is
