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Masteriza [31]
3 years ago
6

A node is a point on a standing wave that has no displacement from the rest position. At the nodes, _____.

Physics
2 answers:
Kitty [74]3 years ago
8 0

Answer: (B) There is complete destructive interference between the incoming and reflected waves

Explanation:

For example, if you pluck a guitar the waves will travel back and forth. They consist of nodes and anti-nodes. It is created, when the wave traveling to one side and bounces of the other end and comes back. As it travels to the other side, it is reflected thus, comes back. So standing waves occurs when there is interference.

When the wave is produced, the points where the string is not moving are called nodes and where they are moving are called anti-nodes. The positions where nodes are produced, destructive interference occurs and where anti-nodes are produced, constructive interference occurs

Debora [2.8K]3 years ago
5 0

Answer:

There is complete destructive interference between the incoming and reflected waves

Explanation:

I did gradpoint

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A 20-newton weight is attached to a spring.
Makovka662 [10]

Answer:

40 N/m

Explanation:

The diagram attached is used to answer the question

We know from Hooke's law that extension is directly proportional to the applied force hence

F=kx where x is extension, F is applied force and k is the spring constant. Making k the subject of the formula then

k=\frac {F}{k}

From the attached diagram extension is given by subtracting unstretched spring from stretched spring hence extension, x=1-0.5=0.5m

Substituting 20 N for F and 0.5 m for x then

k=\frac {20}{0.5}=40 N/m

8 0
3 years ago
Scientific observations should be reported with bias as long as they benefit a scientist's employer
Ira Lisetskai [31]
False, there are always pros and cons to research
8 0
3 years ago
1. How will the ice water mix with the salty water? Write your hypothesis below.
andrew11 [14]
It won't be able to mix because one will not get evaporated and it wont go together
6 0
3 years ago
A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls to the left a 0.5 kg object. What is the acceleratio
lara31 [8.8K]

Answer:

Acceleration is 12m/s^2

Explanation:

We have a resultant force of 10N to the right and a resultant of 4N to the left, since the tow forces are acting in opposite directions, we subtract the two forces to find the net force. The net force would be 6N to the right.

We also know that F=ma, where F=force, m=mass, and a=acceleration

we can rearrange the equation like this,

a=F/m

now we can plug in the known variables

a=6N/0.5kg

a=12m/s^2

8 0
3 years ago
A sample of ore containing radioactive strontium 38Sr90 has an activity of 8.2 × 105 Bq. The atomic mass of strontium is 89.908
ahrayia [7]

From the activity values and the decay constant, the mass of of Strontium in the sample is:

1.62 × 10^{-7}g

<h3>What is the decay constant of an element?</h3>

The decay constant of an element is the probability of decay of a nucleus per unit time.

{λ = ln 2 / t1/2 

where;

t1/2 is the half-life of the isotope.

The half-life is converted to seconds since the decay constant is asked in per seconds.

28.8 years = 28.8 × 3.156 × 10^{7} = 908928000 s \\

Hence;

λ = \frac{ln2}{90892800s} = 7.626 s^{-1}

                                       

The activity of the element, A, the decay constant, λ and the number of nuclei, N are related as follows:

  • A = (–) λN

N = \frac{8.25 ×10^{5}}{7.626×10^{-10}} = 1.082 × 10^{15}              

Molar mass of Strontium-90 is 90 g.

1 mole of Strontium-90 contains 6.02×10^23 nuclei.

The mass, m of Strontium in the sample is calculated:

m = 1.082 × 10^{15} × \frac{90 g}{6.02 × 10^{23}} = 1.62 × 10^{-7}g \\

Therefore, the mass of of Strontium in the sample is:

1.62 × 10^{-7} \: g

Learn more about decay constant at: brainly.com/question/17159453

5 0
2 years ago
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