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shepuryov [24]
3 years ago
10

Suppose your grocery cart is moving at a constant momentum in a straight line down the aisle of a store, without friction. How w

ill the speed change as you drop groceries into the moving cart?
Physics
1 answer:
Strike441 [17]3 years ago
7 0

Answer:

It will increase

Explanation:

The kinetic energy is the energy possessed by a moving object and is given by:

KE = 1/2 mv^2

where m = mass of the object and v = velocity of the object.

It does means that the more the mass of an object in motion, the more the kinetic energy of the object if there are no opposing force such as friction. Also, the more the kinetic energy of the object, the more the speed of that object.

<em>Hence, as the weight of the cart increases by addition of groceries, the kinetic energy increases and the speed also increases as it moves along the frictionless surface.</em>

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7.
stepladder [879]

The resultant of the two vectors is determined as 9.1 units at 83.7⁰.

<h3>Resultant of the vectors</h3>

The resultant of the vectors is calculated as follow;

Sum of vectors in x-direction = (3 - 2)x = x

Sum of vectors in y-direction = (5 + 4)y = 9y

Resultant vector = √(1² + 9²) = 9.1 units

Direction of the vectors = tan⁻¹(y/x) = tan⁻¹(9/1) =  tan⁻¹(9) = 83.7⁰

Thus, the resultant of the two vectors is determined as 9.1 units at 83.7⁰.

Learn more about vectors here: brainly.com/question/25811261

#SPJ1

8 0
2 years ago
Zero, a hypothetical planet, has a mass of 5.3 x 1023 kg, a radius of 3.3 x 106 m, and no atmosphere. A 10 kg space probe is to
Andrej [43]

(a) 3.1\cdot 10^7 J

The total mechanical energy of the space probe must be constant, so we can write:

E_i = E_f\\K_i + U_i = K_f + U_f (1)

where

K_i is the kinetic energy at the surface, when the probe is launched

U_i is the gravitational potential energy at the surface

K_f is the final kinetic energy of the probe

U_i is the final gravitational potential energy

Here we have

K_i = 5.0 \cdot 10^7 J

at the surface, R=3.3\cdot 10^6 m (radius of the planet), M=5.3\cdot 10^{23}kg (mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is

U_i=-G\frac{mM}{R}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{3.3\cdot 10^6 m}=-1.07\cdot 10^8 J

At the final point, the distance of the probe from the centre of Zero is

r=4.0\cdot 10^6 m

so the final potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{4.0\cdot 10^6 m}=-8.8\cdot 10^7 J

So now we can use eq.(1) to find the final kinetic energy:

K_f = K_i + U_i - U_f = 5.0\cdot 10^7 J+(-1.07\cdot 10^8 J)-(-8.8\cdot 10^7 J)=3.1\cdot 10^7 J

(b) 6.3\cdot 10^7 J

The probe reaches a maximum distance of

r=8.0\cdot 10^6 m

which means that at that point, the kinetic energy is zero: (the probe speed has become zero):

K_f = 0

At that point, the gravitational potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{8.0\cdot 10^6 m}=-4.4\cdot 10^7 J

So now we can use eq.(1) to find the initial kinetic energy:

K_i = K_f + U_f - U_i = 0+(-4.4\cdot 10^7 J)-(-1.07\cdot 10^8 J)=6.3\cdot 10^7 J

3 0
3 years ago
What is the speed of a vehicle that travels 50 meters in 5 seconds m/s
katrin [286]

Answer:

10m/s

Explanation:

S=D/T

S=50m/ 5sec (make sure to write correct units, they sometimes mark you on that in physics)

S=10 m/sec (be careful of what the units that they want the answer in, different story if it was m/min

7 0
3 years ago
Read 2 more answers
A truck moving at 20 mph shoots a soccer ball at 20 mph in the opposite direction. How fast is the soccer ball moving? Explain
Brrunno [24]

Answer:

Speed of the soccer ball with respect to ground is ZERO

Explanation:

As we know that truck is moving with speed 20 mph

Now a soccer ball is shoot from truck with respect to the motion of truck in opposite direction

The relative speed of the soccer ball is

v_{bt} = 20 mph

now we know that

v_{bt} = v_b - v_t

so we have

-20 mph = v_b - 20

so we have

v_b = 0

6 0
4 years ago
Question 5 of 10
Nina [5.8K]
It is D 14 MS. West. Kauehfbfnd
6 0
3 years ago
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