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IgorLugansk [536]
4 years ago
5

Which was more difficult to determine (latitude or longitude) and why?

Physics
1 answer:
Ivenika [448]4 years ago
7 0
Longitude was. Determining longitude requires knowing the exact time of day, which was difficult prior to modern clocks. The source book below tells the story of Englishman John Harrison's life-long pursuit of building a reliable clock and its importance to navigation.
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A force vector F1 points due east and has a magnitude of 200N. A second force F2 is added to F1. The resultant of the two vector
PilotLPTM [1.2K]

Answer:

The second vector \vec{F_2} points due West with a magnitude of 600N

Explanation:

The original vector \vec{F_1} points with a magnitude of 200N due east, the Resultant vector \vec{R} points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of  400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:

\vec{F_1}+\vec{F_2}=\vec{R}\implies\vec{F_2}=\vec{R}-\vec{F_1}=-400N-200N=-600N

With the negative sign signifying that the vector points west.

3 0
4 years ago
Three Carnot engines operate between the following temperature limits.
Kipish [7]

Answer:c>a>b

Explanation:

Given

All the engine extracts same amount of heat(Q) from High-temperature reservoir

For a) 400 and 500 K

\eta _{engine}=1-\frac{T_L}{T_H}

\eta _{engine}=\frac{work\ supplied}{heat\ supplied}

1-\frac{400}{500}=\frac{W_a}{Q}

W_a=\frac{Q}{5}

For b)500 K and 600K

1-\frac{500}{600}=\frac{W_b}{Q}

W-b=\frac{Q}{6}

For c) 400 K and 600 K

1-\frac{400}{600}=\frac{W_c}{Q}

W_c=\frac{2Q}{3}

So c will give the highest amount of work

c>a>b

6 0
3 years ago
Which projectiles will be visibly affected by air resistance when they fall?
NemiM [27]
Any object that is launched as a projectile will lose speed and, as a result, altitude, as it travels through the air. The rate at which the object loses speed and altitude depends on the amount of force that way applied to it when it was launched. It is also dependent on the size and shape of the item. This is why something like, say, a football is much faster to fall to the ground than a bullet.
4 0
3 years ago
A plane flies 446 km east from city A to city B in 43.0 min and then 939 km south from city B to city C in 1.10 h. For the total
NeTakaya

Answer:

(a) Magnitude is 1039 km

(b) Direction of the displacement is 64.59^{\circ} South of East

(c) Average velocity magnitude is 570.88 km

(d) The direction of average velocity is 64.59^{\circ} South of East

(e) Average speed is 759.34 km/h

Solution:

Distance moved from A to B in East direction, \vec{AB} = 446 km

Distance moved from B to C in South direction, \vec{BC} = - 939 km

Time taken to move from A to B, t = 43.0 min = 0.72 h

Time taken to move from B to C, t' = 1.10 h

Now,

(a) The magnitude of displacement of the plane is provided by AC as shown in fig 1 and can be given as:

AC = \sqrt{(AB)^{2} + (BC)^{2}}

AC = \sqrt{(446)^{2} + (- 939)^{2}} = 1039 km

(b) Direction of the displacement is given by:

tan\theta = \frac{\vec{BC}}{\vec{AB}}

\theta = tan^{- 1}(\frac{- 939}{\vec{446}}) = - 64.59^{\circ}

64.59^{\circ} South of East

(c) Magnitude of the average speed is given by:

v_{avg} = \frac{AC}{t + t'}

v_{avg} = \frac{1039}{1.82} = 570.88 km/h

(d) The direction of the average velocity is the same as that of the displacement, i.e., 64.59^{\circ} South of East.

(e) The average speed of the [plane is given by:

v'_{avg} = \frac{Total\ Distance\ Traveled}{Total\ Time}

v'_{avg} = \frac{446 + 939}{1.10 + 0.72} = 759.34 km/h

6 0
3 years ago
1. Give 3 examples of waves that carry small amounts of energy?​
masya89 [10]

ANSWER:

  1. Radio waves
  2. Micro waves
  3. Infrared waves

4 0
3 years ago
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