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Vikentia [17]
2 years ago
10

You hold your physics textbook in your hand. (Assume that no other objects are in contact with the book.)

Physics
1 answer:
Jet001 [13]2 years ago
8 0

Answer:

1) the correct answer is b and d

2) For force b its direction is vertical up

   for the force d its direction is vertical down

3) the correct answers are: a, c and d

4) Force a is vertical down , force c is vertical up and force d is vertical down

5) the correct answer which is b

Explanation:

In this exercise it is asked to identify the forces, fundamentally on the free there are the forces of gravity and the support force of the hand, with these facts we answer the questions

1) the correct answer is b and d

the hand acts on the book with a contact force and the Earth acts on the book with the force of gravity.

2) For force b its direction is vertical up

   for the force d its direction is vertical down

3) The forces on the hand are the weight of the book. The force of gravity due to the mass of the hand. As the hand is in balance, there must be a force applied by the arm to keep the hand in position; assuming the hand is in the air, if the hand is resting on the floor the force of the floor on the hand can perform this function

therefore the correct answers are: a, c and d

4) Force a is vertical down

    force c is vertical up

   force d is vertical down

5) The action and reaction forces are forces of equal magnitude, each applied to one of the bodies, we have

* the force of the hand on the free and its reaction the force of the book on the hand

* The force of the Earth on the book and the hand, giving the weight of each one and the relationship is the force of the book and the hand on the Earth

the correct answer which is b

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Given:
1st run: 20 meters North
2nd run: 15 meters East
time: 15 seconds

Average speed = total distance covered / total time taken
Ave. Speed = (20m + 15m) / 15s
Ave. Speed = 35m / 15s
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4 0
2 years ago
If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas
blagie [28]

Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

Option A is correct. (The faster object encounters more resistance)

Air resistance depends on various factors:

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Formula:

F=\frac{1}{2}C_d\rho A v^{2}

As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.

6 0
3 years ago
Are defined as subatomic particles that have more mass than neutrinos but do not interact with light.
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4 0
3 years ago
Question 1 of 25
finlep [7]

Answer:

<em>2.753*10^-11N</em>

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

<em>Hence the gravitational force between the asteroid is 2.753*10^-11N</em>

<em></em>

6 0
2 years ago
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Misha Larkins [42]

Explanation:

Consider the kinematic equation,

x  = vt +  \frac{1}{2} a {t}^{2}

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

x = 3(1.8) +  \frac{1}{2} (9.3) {1.8}^{2}

through simple algebra we get

x = 20.466

where this is the distance traveled in meters.

4 0
3 years ago
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