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SSSSS [86.1K]
2 years ago
14

. A new programming language requires variable names to start with a letter (upper or lowercase), which can be followed by lette

rs, numbers, or underscores. For example, a1_B_3 is a valid name. If every variable name has to be at least 3 characters but fewer than 7, how many variable names are possible?
Physics
2 answers:
cupoosta [38]2 years ago
7 0

Answer:

Explanation:

Total letters available on the keyboard = 26

Doubling this amount to account for both upper and lower case letters.

Therefore, Total characters (Upper + Lower Case) = 52 characters

Total numbers on keyboard (0, 1, 2, 3, 4, 5, 6, 7, 8, 9) = 10 characters

Underscore = 1 character

Thus, Total allowed characters = 52 + 10 + 1 = 63

This is a problem of the permutation as order of the characters results in a different name.

Our file name should be of atleast 3 and smaller than 7 (i.e. 6) characters

Therefore, total possible permutations can be obtained by subtraction permutation of 2 characters from the permutations of 6 characters.

Total\; Permutations\; =\; (^{63}P_{6}) \;-\;(^{63}P_{2}) \\\\Total\; Permutations\; =\;48920775120\;-\;3906\\\\Total\; Permutations\; =\;48920771214

PolarNik [594]2 years ago
6 0

Answer:

1824799399

Explanation:

If we suppose that the letters allow are the 26 letters in the English alphabet, we have a total of 52 letters (Nl) counting upper and lowercase, and we have a total of ten number from zero to nine plus the underscore, for a total of 11 non-alphabetic characters (Nn). To calculate the variables namespace (Ps) we need to add the possibilities of combinations there are from 3 to 6 character (Pn), considering that the first character has to be a letter:

Pn = P3+P4+P5+P6

P3 = Nl*(Nl+Nn)^2 = 206388

P4 = Nl*(Nl+Nn)^3 = 13002444

P5 = Nl*(Nl+Nn)^4 = 819153972

P6 = Nl*(Nl+Nn)^5 = 992436595

Pn = 206388 + 13002444 + 819153972 + 992436595 = 1824799399

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The ball's vertical velocity at the time it just passes over the goal is 0 m/s. Its initial vertical velocity is unknown and we denote it by v\sin39^\circ, where v here is the ball's initial speed. Vertically, the only force acting on the ball is gravity, which attributes a downward acceleration of 9.8 m/s^2. We expect the maximum height achieved by the ball to be 2.4 m, so we can find the initial speed by solving

\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(v\sin39^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm m)

\implies v=11\,\dfrac{\mathrm m}{\mathrm s}

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3 years ago
Does the sun sun traces shortest path across local sky on june solstice
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3 years ago
26. A 40 kg boy jumps from a height of 4m onto a plate-form mounted on springs. As the
denpristay [2]

Answer:

c. 1600J

Explanation:

The loss in potential energy of the boy is given by:

U=mg \Delta h

where

m = 40 kg is the mass of the boy

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h = 4 m + 0.02 m = 4.02 m is the total change in the height of the boy (4 metres + 2 cm due to the compression of the spring)

Substituting, we find

\Delta U = (40 kg)(9.8 m/s^2)(4.02 m) = 1577 J \sim 1600 J

4 0
2 years ago
A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
Aleksandr [31]

Answer:

The acceleration of the crate is 1.8 m/s² so the answer is a.

Explanation:

The very first thing you must do when solving this problem is to draw a free body diagram. (The body diagram is attached to this answer)

So once we got the free body diagram, we can analyze it and build our sum of forces in the x and y directions. Notice that according to the diagram, there are 4 forces to this problem, Normal (N), Weight (W), kinetic friction (fk) and the 750N force.

As one may see in the free body diagram, two of the forces are vertical forces: N and W, so we can use them to build a sum of forces:

Starting with the sum of forces in the y-direction, we get:

ΣF_{y}=0

We set the sum equal to zero because there is no movement in the y-direction, so the system is in vertical equilibrium.

so the sum will be:

N-W=0

when solving for N we get that:

N=W

where W is found by multiplying the mass of the crate by the acceleration of gravity:

N=250kg*9.8m/s²

N=2450N

Once we found the normal force, we can use it to find the kinetic friction which is given by the following formula:

f_{k}=Nμ

where μ is the kinetic friction coefficient.

So we get that the kinetic friction is:

f_{k}=2450N*0.12

so

f_{k}=294

With this information we can go ahead and find the sum of horizontal forces:

ΣF_{x}=ma

In this case the sum is equal to mass times acceleration because the crate is moving horizontally due to the action of a force, so it will have an acceleration.

so the sum of forces look like this:

750N-f_{k}=ma

so

750N-294N=(250kg)a

when solving for a we get:

a=\frac{759N-294N}{250kg}\\ \\a=1.8m/s^{2}

so the crate's acceleration is 1.82m/s².

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If a hypothesis is falsifiable, _____.
san4es73 [151]

Answer:

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Explanation:

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