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bogdanovich [222]
3 years ago
12

A balloon filled with helium gas is found to take 6 hours to deflate to 50% of its original volume. how long will it take for an

identical balloon filled with the same volume of hydrogen gas (instead of helium) to decrease its volume by 50%?
Physics
1 answer:
photoshop1234 [79]3 years ago
5 0
Given:
rate of effusion of Helium = 6 hours

Data needed:
Molar mass of hydrogen gas = 2 g/mol
Molar mass of helium gas = 4 g/mol

Assume:
Constant conditions such as temperature and pressure.

Required:
rate of effusion of Hydrogen gas

Solution:

To solve the problem, we can use the formula:

rate of effusion of A/ rate of effusion of B = (molar mass of B/molar mass of A)^1/2

substituting values,

rate of effusion of hydrogen gas/ 6 hours = (4 g/mol/2 g/mol)^1/2

rate of effusion of hydrogen gas = 8.5 hours
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A 132 cm wire carries a current of 2.2 A. The wire is formed into a circular coil and placed in a B Field of intensity 1 T. a) F
EastWind [94]

Given Information:

Length of wire = 132 cm = 1.32 m

Magnetic field = B =  1 T

Current = 2.2 A

Required Information:

(a) Torque = τ = ?

(b) Number of turns = N = ?

Answer:

(a) Torque = 0.305 N.m

(b) Number of turns = 1

Explanation:

(a) The current carrying circular loop of wire will experience a torque given by

τ = NIABsin(θ)   eq. 1

Where N is the number of turns, I is the current in circular loop, A is the area of circular loop, B is the magnetic field and θ is angle between B and circular loop.

We know that area of circular loop is given by

A = πr²

where radius can be written as

r = L/2πN

So the area becomes

A = π(L/2πN)²

A = πL²/4π²N²

A = L²/4πN²

Substitute A into eq. 1

τ = NI(L²/4πN²)Bsin(θ)

τ = IL²Bsin(θ)/4πN

The maximum toque occurs when θ is 90°

τ = IL²Bsin(90)/4πN

τ = IL²B/4πN

torque will be maximum for N = 1

τ = (2.2*1.32²*1)/4π*1

τ = 0.305 N.m

(b) The required number of turns for maximum torque is

N = IL²B/4πτ

N = 2.2*1.32²*1)/4π*0.305

N = 1 turn

8 0
3 years ago
The ozone layer is found in which layer of the atmosphere
prohojiy [21]

This question is incomplete because the options are missing; here is the complete question

The ozone layer is found in which layer of the atmosphere?

A. Stratosphere

B. Mesosphere

C. Thermosphere

D. Troposphere

The correct answer is A. Stratosphere

Explanation:

The ozone layer as indicated by its name is mainly composed of Ozone (O2), this layer is essential for life because it filters ultraviolet radiation and acts as a greenhouse effect gas by trapping part of the heat from the sun. Additionally, the ozone layer is located in the stratosphere, which is the second layer of the atmosphere and can be found between 20 km to 50 km from Earth's surface. Moreover, the existence of the ozone layer in the stratosphere makes the temperature increase with height due to the radiation of the sun filter by ozone.

4 0
2 years ago
True or False:
mart [117]
This is a true statement
3 0
3 years ago
Read 2 more answers
1. . The maximum current output of a 60 Ω circuit is 11 A. What is the rms voltage of the circuit?
natta225 [31]

Answer:In a DC circuit, the power consumed is simply the product of the DC voltage times the DC current, given in watts.for AC circuits with reactive components we have to calculate the consumed power differently.

a 1/4 watt resistor or a 20 watt amplifier.

3 0
3 years ago
What is the moment of inertia of a 2.0 kg, 20-cm-diameter disk for rotation about an axis (a) through the center, and (b) throug
FinnZ [79.3K]

Answer:

(a) I=0.01 kg.m²

(b) I=0.03 kg.m²

Explanation:

Given data

Mass of disk M=2.0 kg

Diameter of disk d=20 cm=0.20 m

To Find

(a) Moment of inertia through the center of disk

(b) Moment of inertia through the edge of disk

Solution

For (a) Moment of inertia through the center of disk

Using the equation of moment  of Inertia

I=\frac{1}{2}MR^{2}\\  I=\frac{1}{2}(2.0kg)(0.20m/2)^{2}\\  I=0.01 kg m^{2}

For (b) Moment of inertia through the edge of disk

We can apply parallel axis theorem for calculating moment of inertia

I=(1/2)MR^{2}+MD\\ Here\\D=R\\I=(1/2)(2.0kg)(0.20m/2)^{2}+(2.0kg)(0.20m/2)^{2}\\  I=0.03kgm^{2}

8 0
3 years ago
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