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3 years ago

A chemical equilibrium between gaseous reactants and products is shown.

Chemistry

1 answer:

fenix001 [56]3 years ago

3 0

Explanation:

Question 1:

It will shift toward the reactant side as there are a greater number of moles of gas on the reactant side.

Pressure changes only affects only equilibrium involving a gas or gases. An increase in pressure shifts the equilibrium in the direction of the reaction with lower volume.

N₂ + 3H₂ ⇆ 2NH₃

4 2

An increase in pressure will shift the equilibrium towards the product side.

If the pressure is decreased, equilibrium will shifts towards the side of the reactants. This is because the volume of the reactants are higher than that of the product.

Question 2:

True

Based on Le Chatelier's principle, an increase in temperature will shift the equilibrium position towards the products in an endothermic reaction.

An endothermic reaction is a reaction that absorbs heat from the surroundings.

A rise in temperature shifts equilibrium position to the direction that absorbs the heat and vice versa.

In an endothermic reaction, the forward reaction absorbs the heat and therefore equilibrium shifts towards the side of product.

Question 3:

Decreasing the pressure A) Shift to the left

Adding hydrogen gas B) Shift to the right

Adding a catalyst C) No effect

N₂ + 3H₂ ⇆ 2NH₃

Pressure : Decreasing the pressure will shift the equilibrium position to the left. In reactions involving gases, increase in pressure favors the side with a lesser volume. An increase in pressure will favor the formation of ammonia as a product.

A decrease in pressure shifts the equilibrium to the left towards the side of high volume.

Concentration: addition of hydrogen gas will increase the concentration of the gas. An increase in concentration favors the side that uses up the specie and lowers it concentration.

If the concentration of hydrogen gas is increased the equilibrium will shift to the right to annul the concentration of reactants that has increased.

Catalyst: Catalysts have no effect on the position of chemical equilibrium. It only affects the rate at which equilibrium can be reached.

Question 4:

Adding more of gas C to the system

The change that would shift the equilibrium system to the left is by adding more of gas C to the system.

This will increase the concentration of gas C, in order to annul this, the equilibrium will shift to the left.

Heating the system will shift the equilibrium to the right
Increasing volume only affects purely gaseous reactions.
Removing some of gas C from the system shifts the equilibrium to the right.

Question 5:

Heating the system

This is an exothermic reaction because enthalpy change is negative. A rise in temperature shifts equilibrium position to the direction that absorbs heat.

In an exothermic reaction, heat is given off in the forward process. The reverse process is endothermic and heat is absorbed.

Therefore, heating the system will shift the equilibrium to the left and heat is absorbed.

Question 6:

This reaction is exothermic because the system shifted to the left on heating.

It is right to conclude that this reaction is exothermic because the system shifted to the left on heating .

Since the reaction turned dark brown on heating, it shows that more of the reactant Nitrogen dioxide gas was produced.

We can see that the reaction is exothermic in the forward process. An increase in temperature shifts equilibrium position backward to the side that absorbs the heat. This allows for the production of more nitrogen dioxide.

Question 7:

Shift it toward the reactants

A decrease in the concentration of the reactants shift the reaction towards the sides of the reactants.

An increase in concentration of a specie favors the direction that uses up that specie and lowers its concentration.

If the concentration of a specie on the reactant side is increased, equilibrium shifts to the right where more products are formed.

if we decrease the concentration of reactants, the products will be more concentrated and the equilibrium will shift to the left i.e the reactant side.

Learn more:

Equilibrium constant brainly.com/question/11126965

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Combining Boyle's law and Charles' law forms one presure-temperature-volume relationship and holds the mass of the gas constant.

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3 years ago

1. Given the specific heat of lead is 0.129 J/g.C and that it takes 93.4J of energy to

zheka24 [161]

Answer: 40 grams

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since Q = 93.4J

M = ?

C = 0.129 J/g.C

Φ = 40.4°C - 22.3°C = 18.1°C

Then, Q = MCΦ

Make Mass, M the subject formula

M = Q/CΦ

M = (93.4J) / (0.129 J/g.C x 18.1°C)

M = 93.4J / 2.33J/g

M = 40 g

Thus, the mass of the lead is 40 grams

8 0

4 years ago

A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

$Molarity=\frac{moles}{\text{Volume of solution(L)}}$

Moles of glucose = $\frac{18.5 g}{180 g/mol}=0.1028 mol$

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = $\frac{0.1028 mol}{0.1 L}=1.028 mol/L$

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = $M_1=1.208 mol$

Volume of the solution taken = $V_1=30.0 mL$

Molarity of the solution after dilution = $M_2$

Volume of the solution after dilution= $V_2=0.500L = 500 mL$

$M_1V_1=M_2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}$

$M_2=0.07248 mol/L$

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

$0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}$

Moles of glucose = $0.07248 mol/L\times 0.1 L=0.007248 mol$

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0

4 years ago

Sodium hydroxide (NaOH) and hydrochloric acid (HCl) combine to make table salt (NaCl) and water (H2O). Which equation is balance

Art [367]

The equation that is balanced among the given options is the first equation NaOH + HCl → NaCl + H2O

From the question,

We are to determine which of the options gives a balanced equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) to make table salt (NaCl) and water (H₂O)

To do this, we will check which of the given equations is balanced, by checking the equations one after the other.

First, we will define what is meant by balanced equation.

Balanced equations are those whose coefficients result in equal numbers of atoms for each element in the reactants and products

For NaOH + HCl → NaCl + H2O

On the reactants side

Na = 1

O = 1

H = 2

Cl = 1

On the products side

Na = 1

O = 1

H = 2

Cl = 1

Since equal number of atoms of each element are present at both the reactants and products sides, then the equation is balanced

For 2NaOH + 2HCl → 2NaCl + H2O

On the reactants side

Na = 2

O = 2

H = 4

Cl = 1

On the products side

Na = 2

O = 1

H = 2

Cl = 2

The number of atoms of each element present at the reactants side and that present at products side are not equal.

∴ The equation is not balanced

For 2NaOH + HCl → NaCl + H2O

On the reactants side

Na = 2

O = 2

H = 3

Cl = 1

On the products side

Na = 1

O = 1

H = 2

Cl = 1

The number of atoms of each element present at the reactants side and that present at products side are not equal.

∴ The equation is not balanced

For NaOH + 2HCl → NaCl + H2O

On the reactants side

Na = 1

O = 1

H = 2

Cl = 2

On the products side

Na = 1

O = 1

H = 2

Cl = 1

The number of atoms of each element present at the reactants side and that present at products side are not equal.

∴ The equation is not balanced

Hence, the equation that is balanced is the first equation NaOH + HCl → NaCl + H2O

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6 0

2 years ago

Read 2 more answers

Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen

ehidna [41]

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

$4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)$

(b) $C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)$

Multiply the carbon dioxide by 6 to balance carbon as follows:

$C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)$

After that multiply H2O by 7 to balance hydrogen as follows:

$C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)$

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

$C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)$

first balance calcium, by multiply $CaCl_2$ by 3 as follows:

$Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl$

After that balance phosphorous by multiplying $Na_3PO_4$ by 2 as follows:

$2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl$

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

$2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl$

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3 years ago