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lawyer [7]
3 years ago
10

The granite statue of a hero in the local park is discolored.Your friend suggests that the rain will clean the statue.Do you agr

ee? Explain your response
Chemistry
1 answer:
podryga [215]3 years ago
7 0

Answer:

No because the statue is discolored from weathering.

Explanation:

Since the statue was already discolored, that means the substance has been acted upon by a process known as weathering .

Weathering is the breaking down of rocks or dissolving of rocks by the action of rain water, biological activities and temperatures changes. Weathering may be mechanical or chemical . Mechanical weathering live no changes in the overall chemical change of the weathered rock.

Chemical weathering usually occurs when rain water reacts with mineral constituent of rock to form a new minerals like clay and soluble salt. The Chemical changes can be more rapid if the rain water is slightly acidic. The rainwater in the presence of oxygen(oxidation),  because of it acidity may have caused the discoloration of the granite rock. Rain water will likely promotes weathering not the other way round

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What is the mass of a wooden block with a density 2.0 and a volume of 7.0? (Need answer ASAP!!)
Scorpion4ik [409]

Answer:

mass= 14kg

Explanation:

density= mass/volume

so that means mass= volume x density

m= 2kg/m³ x 7m³

m= 14 kg

Hope this helps

5 0
4 years ago
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Arte-miy333 [17]
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3 years ago
What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K
vlada-n [284]

Answer:

=1.666 liters

Explanation:

1 mole of a has at standard temperature and pressure occupies a volume of 22.4 liters.

0.5 moles of nitrogen occupy a volume of (0.5 moles×22.4 dm³/mol)/ 1

=11.2 liters.

Standard pressure= 1 atmosphere (Atm)

Standard temperature = 273.15 Kelvin

According to Combined gas equation, P₁V₁/T₁=P₂V₂/T₂

Let us take the conditions under standard conditions as the reference, with the subscript 1 and the conditions under the 5L container to be scenario 2 with subscript 2.

Therefore P₂ =P₁V₁T₂/T₁V₂

Substituting for the values we get:

P₂= (1 atm× 11.2L ×203K)/ (273K×5L)

=1.666 atm

5 0
3 years ago
"Don't use such phrases here, not cool! It hurts our feelings :( "
lorasvet [3.4K]
I’ve been having problems too honestly lol
5 0
3 years ago
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Determine the ph of a 0.18 m h2co3 solution. carbonic acid is a diprotic acid whose ka1 = 4.3 × 10-7 and ka2 = 5.6 × 10-11. dete
oee [108]
Answer is: ph value is 3.56.
Chemical reaction 1: H₂CO₃(aq) ⇄ HCO₃⁻(aq) + H⁺(aq); Ka₁ = 4,3·10⁻⁷.
Chemical reaction 2: HCO₃⁻(aq) ⇄ CO₃²⁻(aq) + H⁺(aq); Ka₂ = 5,6·10⁻¹¹.
c(H₂CO₃) = 0,18 M.
[HCO₃⁻] = [H⁺<span>] = x.
</span>[H₂CO₃] = 0,18 M - x.
Ka₁ = [HCO₃⁻] · [H⁺] / [H₂CO₃].
4,3·10⁻⁷ = x² / (0,18 M -x).
Solve quadratic equation: x = [H⁺] =0,000293 M.
pH = -log[H⁺] = -log(0,000293 M).
pH = 3,56; second Ka do not contributes pH value a lot.


5 0
3 years ago
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