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Keith_Richards [23]
3 years ago
8

Which statement about the physical properties of matter is true?

Physics
1 answer:
lisov135 [29]3 years ago
4 0

I believe your answer would be D- Physical properties of matter effect the chemical properties of matter.

Hope this helps. Tell me if I'm right.

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A car moves at the speed of 30km/h for 15 mins and then at the speed of 60km/h for the next 15 mins . how much dstance is covere
blagie [28]
Distance = speed x time. The total speed is 30 + 60 = 90km/h and the total time taken is 15 + 15 = 30 minutes. Therefore, you do 90 x 30 = 2700km

Answer = 2700km
6 0
2 years ago
A power source of 2.0 V is attached to the ends of a capacitor. The capacitance is 4.0 μF.
Aleksandr-060686 [28]
Answer:
Q = 8 μC

Explanation:
The relation between voltage, capacitance and charge can be expressed using the following rule:
Q = C * V
where:
Q is the amount of charge that we want to calculate
C is the capacitance = 4 * 10⁻⁶ F
V is the voltage applied = 2 V

Substitute with the givens in the above equation to get the amount of charge as follows:
Q = C * V
Q= 4 * 10⁻⁶ * 2
Q = 8 * 10⁻⁶ Coulumb
Q = 8 μC

Hope this helps :)
7 0
3 years ago
Read 2 more answers
The objective lens in a DVD player must move quickly to keep the laser beam focused on the disc's reflective layer. Why must thi
Zinaida [17]

Explanation:

The small mass of lens in a DVD player accounts for small inertia of the lens. Hence, even on application of force of small magnitude, the lens is rapidly accelerated. Moreover, the small mass of lens also accounts for lower resistance to change in its motion and therefore, again can be rapidly accelerated back and forth.

4 0
3 years ago
Let’s take the case of the 4-kg block with an initial velocity of 10 m/s that is colliding with a 6-kg block that is stationary.
Aleksandr [31]

Answer:

6kg ise yes...............

8 0
1 year ago
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An athlete performing a long jump leaves the ground at a 32.9 ∘ angle and lands 7.78 m away.part a )what was the takeoff speed ?
MatroZZZ [7]

Answer:

Explanation:

Given

Inclination \theta =32.9^{\circ}

Distance of landing point R=7.78\ m

Considering athlete to be an Projectile

range of projectile is given by

R=\frac{u^2\sin 2\theta }{g}

where u=launch velocity

7.78=\frac{u^2\sin (2\times 32.9)}{9.8}

u^2=83.58

u=\sqrt{83.58}

u=9.142\ m/s

(b)If u is increased by 8% then

new velocity is u'=9.87\ m/s

R'=\frac{u'^2\sin 2\theta }{g}

R'=9.07\ m

 

3 0
3 years ago
Read 2 more answers
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