Answer:
Explanation:
Step one:
given data
mass = 7kg
acceleration =2m/s^2
time= 9seconds
acceleration = velocity/time
velocity= acceleration *time
velocity=2*9
velocity= 18m/s
distance moved= velocity* time
distance= 18*9
distance=162m
we also know that the force on impulse is given as
Ft=mv
F=mv/t
F=7*18/9
F=126/9
F=14N
work done = Force* distance
work done=14*162
work=2268Joules
work= 2.27kJ
Answer:
1
Explanation:
The ratio of their nuclear densities is 1, as nuclear density is constant for all nuclei.
The answer to this question is 15 grams
Answer:
The coefficient of static friction between the 10kg block and the surface is 0.29. Which was calculated by applying newtons first law of motion as it applies to equilibrium situations.
Explanation:
The steps for the solution to this problem can be found in the attachment below. The first thing to do in problems like this is to draw free body diagrams that clearly shows the forces acting of the elements of the system. Next, you apply newtons law(s) of motion as the case may be and then solve for your unknowns. It is easier to resolve the forces acting at a point into their horizontal and vertical components. This makes the solution to the problem easier.
For this solution, the sign convention used assumed towards as positive, downwards as negative, the right as positive and the left as negative. Best wishes.