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Reika [66]
3 years ago
8

Imagine that you pushed a box, applying a force of 30 Newton’s , over a distance of 5 meters. How much would you do have done ?

Physics
2 answers:
kati45 [8]3 years ago
7 0
30 ),which is the force,divided by 5
30÷5=6
Sholpan [36]3 years ago
5 0

Answer:

you would have done 150 joules

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Question 27 a motorboat takes 3 hours to travel 144km going upstream. the return trip takes 2 hours going downstream. what is th
Vedmedyk [2.9K]
In this item, we let x be the rate of the boat in still water and y be the rate of the current.

Upstream. When the boat is going upstream, the speed in still water is deducted by the speed of the current because the boat goes against the water. The distance covered is calculated by multiplying the number of hours and the speed.
                 (x - y)(3) = 144

Downstream. The speed of the boat going downstream is equal to x + y because the boat goes with the current.
                (x + y)(2) = 144

The system of linear equations we can use to solve for x is,
                  3x - 3y  = 144
                  2x + 2y = 144

We use either elimination or substitution.
 
We solve for the y of the first equation in terms of x,
                   y =  -(144 - 3x)/3

Substitute this to the second equation,
            2x + 2(-1)(144 - 3x)/3 = 144
The value of x from the equation is 60

<em>ANSWER: 60 km/h</em>
5 0
3 years ago
2) 1. A vibration of an electric charge.
Anestetic [448]

Explanation:

<h2> Answers</h2>

1.Electromagnetic waves

2.Electromagnetic radiation

3.Electromagneticwaves

5 0
3 years ago
Why are many adults and youth in the United states overweight?
Anna11 [10]

Answer:

I'd imagine fast food is a lot more popular than most countries over there and easier to get hold of.

Explanation:

america

6 0
3 years ago
Read 2 more answers
A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
Karolina [17]

Answer:

The average induced emf in the coil is 0.0286 V

Explanation:

Given;

diameter of the wire, d = 11.2 cm = 0.112 m

initial magnetic field, B₁ = 0.53 T

final magnetic field, B₂ = 0.24 T

time of change in magnetic field, t = 0.1 s

The induced emf in the coil is calculated as;

E = A(dB)/dt

where;

A is area of the coil = πr²

r is the radius of the wire coil = 0.112m / 2 = 0.056 m

A = π(0.056)²

A = 0.00985 m²

E = -0.00985(B₂-B₁)/t

E = 0.00985(B₁-B₂)/t

E = 0.00985(0.53 - 0.24)/0.1

E = 0.00985 (0.29)/ 0.1

E = 0.0286 V

Therefore, the average induced emf in the coil is 0.0286 V

3 0
3 years ago
A train has a constant velocity of 2 m/s. east what is the magnitude of the horizontal acceleration of the trian?
kupik [55]

Answer:

0 m/s²

Explanation:

The velocity is constant, so there is no acceleration.

4 0
3 years ago
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