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EastWind [94]
3 years ago
7

1. What is the correct name for S⁻² ion? *

Chemistry
2 answers:
Vlada [557]3 years ago
3 0
This question is too complex but ill answer it since its ez :/

1. Sulfur ion
2. Ga^+3
3. OH⁻ : hydroxide, PO₄⁻³ : phosphate
4. <span>Common names do not provide information about the chemical composition of the compound
5. potassium</span>
MAVERICK [17]3 years ago
3 0
1. sulfide ion (ex. H2S Hydrogen sulfide)

2. Ga 3+

3. OH- & O-2, hydroxide & oxide

4. Common names do not provide info about the chemical composition...

5. Potassiun
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Identify the products of this single-replacement reaction between sulfuric acid and aluminum. Then balance the equation. (2 poin
jeka94

The products of this reaction between aluminum and sulfuric acid are two: hydrogen and aluminum sulfate.

<h3>What are the products in a reaction?</h3>

This concept refers to the substances obtained at the end of the reaction.

<h3>What does it mean to balance an equation?</h3>

It means to make sure there are the same molecules in the reactants and products.

<h3>What are the products in this reaction?</h3>
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<h3>What is the balanced equation?</h3>

2Al + 3H2SO4 = Al2 (SO4)3 + 3H2

Learn more about chemical reaction in: brainly.com/question/3461108

7 0
2 years ago
How many grams of benzene (C6H6) will produce 42 grams of CO2?
3241004551 [841]
The balanced chemical reaction is:<span>

</span><span>2C6H6 + 15O2 → 12CO2 + 6H2O</span><span>

We are given the amount of carbon dioxide to be produced for the reaction. This will be the starting point of our calculations.

</span>42 g CO2 ( 1 mol CO2 / 44.01 g CO2) ( 2 mol C6H6 / 12 mol CO2 ) (78.1074 g C6H6 / 1 mol C6H6) = 12.42 grams of C6H6
7 0
3 years ago
To begin, follow these steps:
s344n2d4d5 [400]

Answer: 6.2  grams of the sodium acetate can dissolve in 5 milliliters of water. if 124 grams of the sodium acetate dissolves in 100 milliliters of water, then 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water.

4 0
3 years ago
Read 2 more answers
A chemist mixes 96.2 g of chloroform with 31.2 g of acetone and 98.1 g of acetyl bromide. Calculate the percent by mass of each
stiv31 [10]

Answer:

42.6 % CHCl₃, 13.83 % C₃H₆O and 43.5 % CH₃COBr

Explanation:

This is a solution with 3 compounds:

96.2 g of CHCl₃

31.2 g of C₃H₆O

98.1 g of CH₃COBr

Total mass of solution is : 96.2g + 31.2 g + 98.1g = 225.5 g

Percent by mass is, the mass of the compounds in 100 g of solution

Let's prepare the rule of three

225.5 g of solution have ____ 96.2 g ___ 31.2 g _____98.1 g

100 g of solution would have ____

(100 . 96.2) / 225.5 = 42.6

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