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Sedbober [7]
3 years ago
13

Which of the following pairs of reactants will react together to produce water (H2O) as one of the products?

Chemistry
2 answers:
marusya05 [52]3 years ago
6 0
These are two questions and two answers.

1) Question: Which of the following pairs of reactants will react together to produce water (H2O) as one of the products?

<span>Fe(OH)₃ and CuO
Cu(OH)₂ and H₂S
MgO and Ca(OH)₂
SO₃ and H₂O
</span>

<span>Answer:
</span>

<span>Cu(OH)₂ and H₂S
</span>

Justification:


1) Fe(OH)₃ and CuO: to form water Cu and Fe should react with each other. Being them two metals, they will not do that. So this reaction is not possible.

2) Cu(OH)₂ and H₂S: Being S a non metal and Cu a metal, they can react to form a the salt CuS, and water, as per this equation:


<span>Cu(OH)₂ + H₂S → CuS + 2H₂O
</span>

<span> 3) MgO and Ca(OH)₂: Being Mg and Ca two metals they will not react with each other, so this reaction is not feasible.
</span>

<span>4) SO₃ and H₂O: this is an acid oxide and water reaction which yields to an acid, as per this equation:
</span>

<span>SO₃ + H₂O → H₂SO₄
</span>

Which is not producing water


<span>2) Question: Based on reactivity, which of the following elements can replace aluminum (Al) in a compound during a single replacement reaction?

B
Ca
Zn
Fe
</span>

Answer: Ca.

Justification:

Only an element more reactive than Al will replace it <span>in a compound during a single replacement reaction.</span>

You may predict that being Ca an alkalyne earth element it is more reactive than Al and so Ca will replace Al.

Else,  you have to search a reactivity table, where you will find this order of reactivity among the metals:

Ca more reactive than Al

Al more reactive than Zn

Zn more reactive than Fe.
<span />

Being B a metalloid, its matallic character is low and it is less reactive than the other metals on the list.


Dima020 [189]3 years ago
3 0

Answer: 1. Option (b) is the correct answer.

              2. Option (b) is the correct answer.

Explanation:

1. The reaction between the given reactants will be as follows.

(a) Fe(OH)_{3} + CuO \rightarrow Fe_{2}O_{3} + Cu(OH)_{2}

(b) Cu(OH)_{2} + H_{2}S \rightarrow CuS + H_{2}O

(c) MgO + Ca(OH)_{2} \rightarrow Mg(OH)_{2} + CaO

(d) SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}

Thus, out of the given options, the reaction Cu(OH)_{2} + H_{2}S \rightarrow CuS + H_{2}O results in the formation of water.


2.  Base on reactivity series, the reactivity of some metals in the decreasing order is as follows.

                  K, Na, Ca, Mg, Al, Zn, Fe

Whereas B is a metalloid so, it will have properties of both metals and non-metals. Thus, boron (B) will also be less reactive than Al.

Therefore, out of the given options, Ca is more reactive than Zn and Fe.

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Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
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<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

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