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Andrew [12]
3 years ago
8

A group of students conducted several trials of an experiment to study Newton’s second law of motion. They concluded that tripli

ng the mass required tripling the net force applied. What quantity were the students holding constant?
Physics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

1) Mass and acceleration

2) 4.0

3)When the net force applied to an object changes, the acceleration changes by the same factor.

4)acceleration

5)The acceleration is half of its original value

Explanation:

A wise man once said if you cheat together you succeed together! lol i am jk  

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When calculating the power bill, power companies use _____.
Dovator [93]
I think the correct answer from the choices listed above is option B. When calculating the power bill, power companies use kilowatt-hours. This unit is a derived unit of energy equal to 3.6 MJ. If energy is being transmitted or used at a constant rate (power) over a period of time, the total energy in kilowatt-hours is the product of the power in kilowatts and the time.
5 0
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A body is accelerated continuously. What is the form of the graph
Andrej [43]

Answer:

If a body is constantly accelerating the graph would be one-quadrant

4 0
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Why are you able to observe the Doppler effect on earth with sound waves but not with light waves?
VladimirAG [237]

Answer: When an ambulance passes with its siren blaring, you hear the pitch of the siren change: as it approaches, the siren’s pitch sounds higher than when it is moving away from you. This change is a common physical demonstration of the Doppler effect.

Explanation:

6 0
3 years ago
How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?
sdas [7]
The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
W=q \Delta V
where q is the charge and \Delta V is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is \Delta V = 9.0 V, so we can find the charge transferred by the battery:
q= \frac{W}{\Delta V}= \frac{39 J}{9.0 V}=4.33 C
3 0
3 years ago
On a Saturday afternoon, you decide to pay a neighborhood kid to mow your lawn. The kid usesa manual push lawn mower with a mass
Mars2501 [29]

Answer with Explanation:

We are given that

A.Mass,m=12 kg

\theta=53^{\circ}

\mu_k=0.16

Speed,v=1.5m/s

Net force in x direction must be zero

F_{net}=0

Fsin\theta-f=0

Fsin\theta=f

Net force in y direction

N-mg-Fcos\theta=0

N=mg+Fcos\theta

f=\mu_kN=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_kmg+\mu_kFcos\theta

Fsin\theta-\mu_kFcos\theta=\mu_kmg

F(sin\theta-\mu_kcos\theta)=\mu_kmg

F=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}

Power,P=Fv

P=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}v

Where g=9.8m/s^2

B.Substitute the values

P=\frac{0.16\times 12\times 9.8}{sin53-0.16cos53}\times 1.5

P=40.17W

6 0
3 years ago
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