A spring with a spring constant of 1200 N/m has a 55-g ball at its end. The energy of the system is 5.5J. What is the amplitude
2 answers:
Answer:
0.0957 m
Explanation:
The total energy of a spring system is given by:
where
k is the spring constant
A is the amplitude of the vibration
In this problem, we know:
k = 1200 N/m is the spring constant
E = 5.5 J is the total energy
Therefore, we can re-arrange the equation to find the amplitude of the vibration:
You reach the max amplitude when all the energy is in the spring and the kinetic energy of the ball is zero.
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They all have the same aphelion distances
Answer:
a=-1.58 m/s^2
Explanation:
Vo=34m/s
Vf=15m/s
t=12s
a= dV/dt = (Vf-Vo) /t = (15-34)/12
= - 19/12 = - 1.58m/s2
sure. you can talk with me. wassup?
Each ball :
P = m * m/sec
P = 1.0 * 5
P = 5.0 kg.m/sec
in stationary :
P = 1.0 kg * 0.0
P = 0.0 kg.m/sec
hope this helps!
Answer:
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Explanation:
The plot is asymptotic to the x and y axes in the first and third quadrants