-- If the field were inclined to the surface, then it would have
some component parallel to the surface.
-- Then, since we're talking about a conductor, the charges
on the object would move in response to that component
of the field, until there was no longer any component of the
field trying to move them.
Answer:
wish I could help
Explanation:
I been rereading this and I can't solve it lemme go ask people in ma house real quick
A b c d e f g h i j k l m
P = 10^5 - ρ (average)gh
where ρ (average) = average air density between 0 and 5000 m = (1.22+0.74)/2 = 0.98
we know g & h
I get P = 52470 Pa
