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agasfer [191]
2 years ago
10

For metallurgical reasons, it is desirable to melt the weld metal with minimum energy input. Which one of the following heat sou

rces is most consistent with this objective: (a) high power, (b) high power density, (c) low power, or (d) low power density?
Engineering
1 answer:
stellarik [79]2 years ago
8 0

Answer:

The correct option is;

(a) High power density

Explanation:

The power density of a material is the amount of power per unit volume of the material. Power density, in the context of transformers, fuel cells, batteries, motors, and power supply units, is measured with respect to the volume, and the units is given as W/m³

A system such as a capacitor with an high power density has the capacity to put out large energy amount from a small volume. A capacitor with a high power density, can produce the same power output as a car battery and is said to have a high power density.

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A 13.7g sample of a compound exerts a pressure of 2.01atm in a 0.750L flask at 399K. What is the molar mass of the compound?a. 3
Katarina [22]

Answer: Option D) 298 g/mol  is the correct answer

Explanation:

Given that;

Mass of sample m = 13.7 g

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Volume V = 0.750 L

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Now taking a look at the ideal gas equation

PV = nRT

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n = PV/RT

now we substitute

n = (2.01 atm x 0.750 L) / (0.0821 L-atm/mol-K x 399 K )

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we know that

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Molar Mass = 13.7 g / 0.04601 mol

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A 11.5 nC charge is at x = 0cm and a -1.2 nC charge is at x = 3 cm ..At what position or positions on the x-axis is the electric
diamong [38]

Answer:

Explanation:

Given

q_1=11.5\ nC charge is placed at x=0\ cm

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so net electric field is zero somewhere beyond negatively charged particle

Electric Field due to q_2 at some distance r from it

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Now Electric Field due to q_1 is

E_1=\frac{kq_1}{(3+r)^2}

Now E_1+E_2=0

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\frac{3+r}{r}=3.095

thus r=1.43\ cm

Thus Electric field is zero at some distance r=1.43 cm right of q_2

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