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3 years ago

A dog is 10 m from a cat, whose speeds are 6 and 5 m / s, respectively. What time does the dog require to catch the cat?

Physics

1 answer:

scoray [572]3 years ago

4 0

Answer:

10 seconds

Explanation:

because the cat is moving one m/s slower than the dog, the dog has a relative speed of 1 m/s. 10 meters would take 10 seconds for the dog to cover

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A meter stick with a mass of 0.167 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me

SSSSS [86.1K]

Answer:

Part a)

change in potential energy is given as

$\Delta U = 0.82 J$

Part B)

angular speed of the rod is given as

$\omega = 5.42 rad/s$

Part c)

Linear speed of the end of the rod is given as

$v = 5.42 m/s$

Part d)

when a particle falls from rest to distance d = 1 m

$v = 4.42 m/s$

Explanation:

Part A)

As we know that the gravitational potential energy change is given as

$\Delta U = mgH$

$\Delta U = 0.167(9.81)(0.5)$

$\Delta U = 0.82 J$

Part B)

As we know that change in gravitational energy is equal to gain in kinetic energy

so we have

$\Delta U = \frac{1}{2}I\omega^2$

$0.82 = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

$\omega^2 = \frac{6 \times 0.82}{0.167 (1)^2}$

$\omega = 5.42 rad/s$

Part c)

Linear speed of the end of the rod is given as

$v = L\omega$

$v = 5.42 m/s$

Part d)

when a particle falls from rest to distance d = 1 m

so we will have

$v = \sqrt{2gL}$

$v = \sqrt{2(9.81)(1)}$

$v = 4.42 m/s$

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3 years ago

Two events are observed in a frame of reference S to occur at the same space point, with the second event occurring after a time

Deffense [45]

Answer:

he difference between the positions of the two events as measured in S = 4.42 x 10 8 m

Explanation:

The concept of time dilation is applied to solve the question as shown in the attachment.

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3 years ago

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Self-fulfilling prophecy is a primary example of the capability of language to
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3 years ago

WILL GIVE BRAINLIEST! Briefly describe the three phases of self-regulation. _PSYCHOLOGY_

Zinaida [17]

Phase 1. Forethought/preaction—This phase precedes the actual performance; sets the stage for action; maps out the tasks to minimize the unknown; and helps to develop a positive mindset. Realistic expectations can make the task more appealing. Goals must be set as specific outcomes, arranged in order from short-term to long-term. We have to ask students to consider the following:

When will they start?Where will they do the work?How will they get started?What conditions will help or hinder their learning activities are a part of this phase?

Phase 2. Performance control—This phase involves processes during learning and the active attempt to utilize specific strategies to help a student become more successful.

We have to ask students to consider the following:

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We have to ask students to consider the following:

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3 years ago

Read 2 more answers

Your GPS shows that your friend’s house is 10.0 km away. But there is a big hill between your houses and you don’t want to bike

kati45 [8]

Answer:

The value is $c = 8 \ km$