The formula of the missing component are a follows
HBr + KOH ------> KBr + H2O
H2SO4 + 2NH4OH--------> (NH4)2SO4 + 2H2O
2HNO3 + Mg(OH)2 ---------> Mg(NO3)2 + 2 H2O
the mass of a carbon atom is 1.994 x 10⁻²³ g
the mass of the carbon sample is 12.01 g
to find the number of Carbon atoms we have to divide the mass of sample by mass of a carbon atom.
number of C atoms =
therefore number of atoms = 6.023 X 10²³ atoms of carbon
Answer:
1.97 moles of Na contains greater number of atoms than 6.8 × 10²² atoms of Li.
Explanation:
To solve this problem we will first calculate the number of atoms contained by 1.97 moles of Na and then will compare it with 6.8 × 10²² atoms of Li.
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of atoms contained by 1.97 moles of Na, we will use following relation,
Moles = Number of Atoms ÷ 6.022 × 10²³ atoms.mol⁻¹
Solving for Number of Atoms,
Number of Atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting values,
Number of Atoms = 1.07 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of Atoms = 1.18 × 10²⁴ Atoms of Na
Hence,
1.97 moles of Na contains greater number of atoms than 6.8 × 10²² atoms of Li.
Answer: the answer is c.
Explanation:
i juss guessed and it was right?
