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Sergio [31]
4 years ago
8

Liquid water first appears after _______ minutes?

Chemistry
2 answers:
steposvetlana [31]4 years ago
6 0

The answer is B.) 3

Because Segment 2 shows the condensation of water from the gas phase to the liquid phase. <u>It is during this segment that liquid water first appears.</u> Therefore, after 3 minutes, liquid water first appears.

tino4ka555 [31]4 years ago
5 0

Answer: IT'S B

Explanation:

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B

Explanation:

It's the only anwse that makes sense

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3. What will you observe (the dependent variable) as a result of that change?
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What is the percent by mass of 54.7g of calcium chloride dissolved in 500g of water?
Advocard [28]
% by mass = (mass solute/mass solution)*100%
mass  of the solute = 54.7 g
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3 0
4 years ago
How many lead atoms in Pb(OH) 4 ?
OlgaM077 [116]

4 in hydrogen 4 in oxygen

Explanation:

hope this helps

5 0
3 years ago
Please help! Thanks!
olya-2409 [2.1K]

Answer:

<u>The deviations are :</u>

  • <u>The activation energy which changes with temperature</u>
  • <u>The arrhenius constant which depends on the temperature</u>

Explanation:

  • There are deviations from the Arrhenius law during the glass transition in all classes of glass-forming matter.
  • The Arrhenius law predicts that the motion of the structural units (atoms, molecules, ions, etc.) should slow down at a slower rate through the glass transition than is experimentally observed.
  • In other words, the structural units slow down at a faster rate than is predicted by the Arrhenius law.
  • <em>This observation is made reasonable assuming that the units must overcome an energy barrier by means of a thermal activation energy. </em>
  • The thermal energy must be high enough to allow for translational motion of the units <em>which leads to viscous flow of the material.</em>

  • Both the Arrhenius activation energy and the rate constant k are experimentally determined, and represent macroscopic reaction-specific parameters <em>that are not simply related to threshold energies and the success of individual collisions at the molecular level. </em>
  • Consider a particular collision (an elementary reaction) between molecules A and B. The collision angle, the relative translational energy, the internal (particularly vibrational) energy will all determine the chance that the collision will produce a product molecule AB.
  • Macroscopic measurements of E(activation energy) and k(rate constant ) <em>are the result of many individual collisions with differing collision parameters. </em><em>They are averaged out to a macroscopic quantity.</em>
6 0
3 years ago
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