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olga_2 [115]
4 years ago
6

Newton’s first and second laws interactive reader

Physics
1 answer:
lisov135 [29]4 years ago
5 0
<span>La segunda ley de Newton se conoce como la ley del movimiento de las partículas. <span>Dice que si sobre un cuerpo de masa en una sola fuerza Féliz que recibe una descarga de tal que F = ma. 
</span></span>Y la primera  <span>establece que un objeto permanecerá en reposo o con movimiento unifome rectilíneo al menos que sobre él actúe una fuerza externa.
Espero q te sirva :)</span>
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Laasya accurately explains to Clark the role of decomposers in an ecosystem. Choose the sentences that she should include in her
Brrunno [24]

The Sentences which should Include in Laasya Explanation are :

B. Decomposers breakdown Dead Organisms.

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<u>Because </u>:

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3 years ago
The Earth is 149.6 million km from the Sun. What is this distance also known as?
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It's as far as I remember one Astronomical Unit
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fenix001 [56]

The teacher measured the maximum height and the minimum height of ...

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3 years ago
If you're ever standing on a mountaintop when a dark cloud passes overhead and your hair stands up, get off the mountain fast. H
OleMash [197]

Answer:

The hairs would have acquired charge by the passing of dry winds resulting in the loss of electron.

Explanation:

While standing on the top of a mountain if a person gets its hairs stand up after a cloud passes over, this might happen due to the static electric charges on the lower surface of the cloud  are opposite in nature to that of hairs which the hairs would have acquired by the passing of dry winds which would have resulted in the loss of electron from the hair tip.

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8 0
4 years ago
A car drives over a hilltop that has a radius of curvature 0.120 km at the top of the hill. At what speed would the car be trave
Mashutka [201]

Answer:

34.3 m/s

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where

(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity

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The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find:

v=\sqrt{gr}=\sqrt{(9.8 m/s^2)(120 m)}=34.3 m/s

6 0
3 years ago
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