To arrange these elements according to the atomic radius (smallest to largest) would be:
Be, Mg, Ca, Sr, Ba
amount of time the two substances are in contact. area in contact between the two substances. specific heat of the material that makes up the substances. the density of the two substances in contact.
Answer:
ok
Explanation:
Element %composition Mol. mass No. of C atoms Simplest Rounding
ratio off
C 82.76 12 6.89 1× 2 2
H 17.24 1 17.24 2.5× 2 5
Number of carbon atoms present =
12
82.76
=6.89
Number of hydrogen atoms present =
1
17.24
=17.24
simplest ratio =
6.89
6.89
=1
simplest ratio =
6.89
17.24
=2.5
∴ Empirical fromula is C
2
H
5
Empirical formula mass= 2×12+5 = 29
∴ V.D. = 29
Mol. mass = 2 × V.D.
=58
n=
Empiricalformulamass
Molecularmass
=
29
58
=2
∴ Molecular formula = C
4
H
10
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Ok I can help I know this I’m good): sikeeee
Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.
Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.