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3 years ago

What is the mass of 22.4 L of H2O at STP?

1 answer:

6 0

The mass of 22.4 L of H2O at STP IS 18.0 grams

calculation

mass = moles x molar mas
Calculate the moles of water at STP

At STP 1 mole =22.4 L
what about 22.4 l of H2O

by cross multiplication

1mole x22.4 L/22.4 L = 1 mole

molar mass of water = (1 x2) + 16 =18 g/mol

moles is therefore = 8 g/mol x 1 mol = 18 grams

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Eddi Din [679]

INFORMATION:

We have the following statements

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STEP BY STEP EXPLANATION:

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- A liquid has a definite volume and has not a definite shape

- A gas has not a definite volume and has not a definite shape

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- A solid has a definite volume and has a definite shape

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1 year ago

Air is an example of a mixture because the elements and compounds that make up air retain their individual properties. True Fals

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3 years ago

Read 2 more answers

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0

3 years ago

The three states of matter differ primarily in terms of shape and volume. Describe solids, liquids and gases in these terms.

schepotkina [342]

Answer:

solids have definite shape and volume. liquid have definite volume but not definite shape. gases do not have definite volume as well as definite shape.

8 0

3 years ago

If you have 1.1 moles of magnesium nitrate then how many grams is that

marysya [2.9K]

Answer: 162.8 grams

Explanation:

Magnesium nitrate has a chemical formula of Mg(NO3)2.

Given that:

Number of moles of Mg(NO3)2 = 1.1 moles

Mass in grams of Mg(NO3)2 = ?

For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g

Mg(NO3)2 = 24g + (14g + 16gx3) x 2

= 24g + (14g + 48g) x 2

= 24g + (62g) x 2

= 24g + 124g

= 148g/mol

Now, apply the formula:

Number of moles = Mass in grams / molar mass

1.1 moles = Mass / 148g/mol

Mass = 1.1 moles x 148g/mol

Mass = 162.8 grams

Thus, there are 162.8 grams of magnesium nitrate.

3 0

3 years ago