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kykrilka [37]
4 years ago
6

While Sophia was driving to work, she tried to avoid hitting an animal and instead hit a parked car. As the car stopped, her bod

y continued to move forward at the same speed and in the same direction.
What happened to Sophia’s body in the car accident is an example of
Physics
1 answer:
Andreyy894 years ago
7 0
This would be an illustration of Newton's first law of motion. Law of inertia, an object moving at constant velocity will keep moving at constant velocity until a force is acted upon it. Inertia is the tendency of an object to keep moving in a particular direction resisting to change, unless a force acts upon the object.
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If I was driving at 50 miles an hour and hit a car at a stop light, how would there car react after it is hit?
MA_775_DIABLO [31]

Answer:

The answer is  C.move forward rapidly until stopped.

Explanation:

50 miles an hour is a very high speed. The momentum transfer to the car at stop light will move the car forward rapidly until its brake is able to stop it.

4 0
3 years ago
Read 2 more answers
a disk initially at rest rotates with constant angular acceleration through an angel of 50 rad in 5 sec find the angular speed o
lisov135 [29]

Recall the formula,

∆<em>θ</em> = <em>ω</em>₀ <em>t</em> + 1/2 <em>α</em> <em>t</em> ²

where ∆<em>θ</em> = angular displacement, <em>ω</em>₀ = initial angular speed (which is zero because the disk starts at rest), <em>α</em> = angular acceleration, and <em>t</em> = time. Solve for the acceleration with the given information:

50 rad = 1/2 <em>α</em> (5 s)²

<em>α</em> = (100 rad) / (25 s²)

<em>α</em> = 4 rad/s²

Now find the angular speed <em>ω </em>after 3 s using the formula,

<em>ω</em> = <em>ω</em>₀ + <em>α</em> <em>t</em>

<em>ω</em> = (4 rad/s²) (3 s)

<em>ω</em> = 12 rad/s

3 0
3 years ago
Consider a uniformly charged non-conducting semicircular arc with radius r and total negative charge Q. The charge on a small se
Mazyrski [523]

Answer: Magnitude of electric field = 6.77×10^11N/C

Explanation: Electric field= E =KQ/ r ^2

Given:

Total charge Q=53.2nc

Radius 84cm= 0.84m

Coulombs constant K= 8.987x10^9NmC^-1

E =(( 8.987×10^9) × 53.2) /(0.84^2)

E = ( 4 . 777 ×10 ^ 9 )/ 0.7056

E = 6.77 × 10^ 11 NC^-1

3 0
3 years ago
The area of the effort and load of the Piston of a hydrolic are 0.5 and 5m respectively. If a force of 100 Newton is applied on
Yanka [14]

Answer:

Explanation:

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Pressure is given as force/area

P1=P2

Then,

F1/A1=F2/A2

Cross multiply

F1A2=F2A1

Given that

Ae=0.5m² area of effort

Al=5m² area of load

Fl=? Force if load

Fe= 100N. Force of effort

Then applying pascal

Fl/Al=Fe/Ae

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FL/5=200

Fl=200×5

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6 0
4 years ago
In a catapult, energy is transferred into useful kinetic energy stores. What store is the energy in when it is the catapult?
yawa3891 [41]

Answer:

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