Since my givens are x = .550m [Vsub0] = unknown
[Asubx] = =9.80
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0]
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])
Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in
0^2 = [Vsub0x]^2 + 2[-9.80]*(.550)
0 = [Vsub0x]^2 -10.78
10.78 = [Vsub0x]^2
Sqrt(10.78) = 3.28 m/s
Answer:
46.22 cm
Explanation:
The focal refraction, fr is given by
The focal red light is given by
and making fr the subject we obtain
fv = 0.945455* 16.70886 cm = 15.79747 cm
Therefore, violet image is approximately 46.22 cm
Answer:
second is the SI unit of time
The base unit of length in the international system of units is the: meter (m)
<h3>Meter</h3>
The meter, ( symbol: m ) is the SI unit of length. It is derived by taking the fixed numerical value of the speed of light in vacuum c to be 299 792 458 when expressed in the unit m s-1
<h3>International system of unit ( SI ) base units</h3>
The SI base units are the standard units of measurement defined which is defined by the International System of Units (SI) for the seven base quantities of what is now known as the International System of quantities:
Learn more about SI base units:
brainly.com/question/16393390
Answer: Your question is missing below is the question
Question : What is the no-friction needed speed (in m/s ) for these turns?
answer:
20.1 m/s
Explanation:
2.5 mile track
number of turns = 4
length of each turn = 0.25 mile
banked at 9 12'
<u>Determine the no-friction needed speed </u>
First step : calculate the value of R
2πR / 4 = πR / 2
note : πR / 2 = 0.25 mile
∴ R = ( 0.25 * 2 ) / π
= 0.159 mile ≈ 256 m
Finally no-friction needed speed
tan θ = v^2 / gR
∴ v^2 = gR * tan θ
v = √9.81 * 256 * tan(9.2°) = 20.1 m/s
