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Lady bird [3.3K]
3 years ago
9

1. Which of the following is an example of a physical change to matter?

Chemistry
2 answers:
sertanlavr [38]3 years ago
6 0
1. C. Freezing
2. B. Dissolving salt in water
Ostrovityanka [42]3 years ago
4 0

Answer:

1) FREEZING

2)DISOLVING SALT IN WATER

Explanation:

A physical change is the one that can be easily reversed and there is no new substance formed. However , physical change can always be reversible.

For instance the separation of mixtures by evaporation is physical change.

As we have physical change there is also a chemical change which a change that's cannot be reversed easily and there's no new substance formed. Examples are addition of water to quicklime, fermentation of substance,melting a stick of butter

,using magnesium to displace hydrogen gas from water.

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Answer: C

Explanation:

According to Neils Bohr, atoms contain electrons which are arranged in energy levels. The energy levels proceed from the lowest to the highest. When energy is supplied to an atom,it moves from lower to higher energy levels. The higher energy level is known as the excited state. Excited states are short lived and atoms quickly return to ground state with emission of the absorbed energy in the form of visible light. This visible light must have one of the seven colours observed in the visible spectrum; Red, orange, yellow, indigo, blue, green, violet. Energy required for this excitation is supplied by heating the substance in a flame.

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Answer:

I would expect to extract the acetic acid.

Explanation:

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In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.

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3 years ago
A reaction has a forward rate constant of 2.3 × 106 s-1 and an equilibrium constant of 4.0 × 108. what is the rate constant for
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Answer is: 5,75·10⁻¹.
Kf = 2,3·10⁶ 1/s.
K = 4,0·10⁸ 1/s.
Kr = ?
Kf - <span>forward rate constant.
K - </span><span>equilibrium constant.
Kr - </span><span>reverse rate constant.
</span>Since both Kf and Kr are constants at a given temperature, their ratio is also a constant that is equal to the equilibrium constant K.<span>
K = Kf/Kr.
Kr = Kf/K = </span>2,3·10⁶ 1/s ÷ 4,0·10⁸ 1/s = 5,75·10⁻¹.

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