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givi [52]
3 years ago
14

a kid is on a skate board going 14kph and trows a set of keys on the ground at 8kph. the spped of the keys relitive to the gound

is?
Physics
1 answer:
Vanyuwa [196]3 years ago
5 0
To determine the speed relative to the ground, since the ground is our reference frame, it would be v = 0, for the kid on the skateboard, you would need to take into account the speed that he/she is going and the speed of the keys thrown at.

I believe.
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. Egbert is in a rowboat four miles from the nearest point on Egbert a straight shoreline. He wishes to reach a house 12 miles f
swat32

Answer:

t=\frac{13}{3} =4.33\ mi.hr^{-1}

Explanation:

Given:

  • Distance from the shore, s=4\ mi
  • distance of house from the shore, h=12\ mi
  • speed of rowing, v_r=3\ mi.hr^{-1}
  • speed of walking, v_w=4\ mi.hr^{-1}

<em>For the least amount of time to reach the house one must row at the nearest point on the shore and then walk from there.</em>

<u>Now the time taken to reach the shore:</u>

t_s=\frac{s}{v_s}

t_s=\frac{4}{3}\ mi.hr^{-1}

<u>Time taken in walking to house from the shore:</u>

t_h=\frac{h}{v_w}

t_h=\frac{12}{4}

t_h=\frac{12}{4}

t_h=3\ mi.hr^{-1}

<u>Therefore total time taken:</u>

t=t_h+t_s

t=\frac{13}{3} =4.33\ mi.hr^{-1}

6 0
3 years ago
In transduction, the cochlea is part of this structure:
anyanavicka [17]

Answer:

wats up

Explanation:

8 0
3 years ago
26. What are the 2 conditions required for work to occur?
erica [24]
The first is that the object moves. The second is that a force must act on the object in the direction the object moves.
4 0
3 years ago
Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele
JulijaS [17]

Answer: 4.86(10)^{-12}m

Explanation:

The Compton Shift \Delta \lambda in wavelength when photons are scattered is given by the following equation:

\Delta \lambda=\lambda' - \lambda_{o}=\lambda_{c}(1-cos\theta) (1)  

Where:  

\lambda'=500 nm=500(10)^{-9} m is the wavelength of the scattered photon

\lambda_{o}  is the wavelength of the incident photon

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}.c}, being h=4.136(10)^{-15}eV.s the Planck constant, m_{e} the mass of the electron and c=3(10)^{8}m/s the speed of light in vacuum.  

\theta=180\° the angle between incident phhoton and the scatered photon.  

\Delta \lambda=2.43(10)^{-12} m (1-cos(180\°)) (2)

\Delta \lambda=4.86(10)^{-12}m (3)  This is the shift in wavelength

5 0
3 years ago
Need help... 44 points!!!!
vladimir1956 [14]

As per conditions described here we know that all force arrow are not of equal length

So all forces are not same in magnitude

Here applied force on right direction is more in magnitude then the friction force on left

So it will have net unbalanced force towards right due to which it will move towards right direction or in the direction of net unbalanced force

While in the upward and downward direction the forces are balanced and hence the box will not move in that direction

So normal force will be balanced by gravitational force

So here answer will be

The forces acting on the box are <u>UNBALANCED</u> .

The box will move to the <u>RIGHT</u> .

7 0
4 years ago
Read 2 more answers
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