How do you start the game of floor hockey

A solid non-conducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a radius r (r <

Svet_ta [14]

Answer:

Hence the answer is E inside $= KQr_{1} /R^{3}$ .

Explanation:

E inside $= KQr_{1} /R^{3}$

so if r1 will be the same then

E $\begin{bmatrix}Blank Equation\end{bmatrix}$ proportional to 1/R3

so if R become 2R

E becomes 1/8 of the initial electric field.

8 0

3 years ago

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Your class decides to build a circuit to make a light bulb shine. When you are finished, you have a setup with wires, a light bu

Evgesh-ka [11]

The answer to this question would be B (the battery is the electrical power supply)

6 0

3 years ago

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A reconnaissance plane flies 560 km away from its base at 602 m/s, then flies back to its base at 903 m/s.

IrinaVladis [17]

Answer:

Approximately $722\; \rm m\cdot s^{-1}$ .

Explanation:

The average speed of a vehicle is calculated as:

$\displaystyle \text{average speed} = \frac{\text{total distance}}{\text{total time}}$ .

In this question, the total distance is $2 \times 560\; \rm km = 1120\; \rm km$ .

The unit of the speeds in this question is meters per second, while the unit of distance is kilometers. Convert the unit of distance to meters:

$560 \; \rm km = 560 \times 10^{3} \; \rm m = 5.6 \times 10^{5}\; \rm m$ .

$1120 \; \rm km = 1120 \times 10^{3} \; \rm m = 1.12 \times 10^{6}\; \rm m$ .

Time required for the first part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{602\; \rm m\cdot s^{-1}} \approx 930\; \rm s$ .

Time required for the second part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{903\; \rm m\cdot s^{-1}} \approx 620\; \rm s$ .

The time required for the entire trip would be approximately $930 + 620 = 1550\; \rm s$ .

Calculate the average speed of this plane:

$\begin{aligned} \text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &\approx \frac{1.12\times 10^{6}\; \rm m}{1550\; \rm s} \approx 722\; \rm m \cdot s^{-1}\end{aligned}$ .

6 0

2 years ago

How do you add vectors in two dimensions

noname [10]

Explanation:

Use the magnitude and direction of each vector to find its components. Add the components that are along the same dimension. Then use Pythagorean theorem and trigonometry to find the magnitude and direction of the resultant vector.

For example, if we have a vector of magnitude A and direction α, and another vector of magnitude B and direction β, then the components of the first vector are:

Ax = A cos α

Ay = A sin α

And the components of the second vector are:

Bx = B cos β

By = B sin β

The resultant vector (we'll call it C) has components:

Cx = Ax + Bx

Cy = Ay + By

The magnitude of the resultant vector is:

C = √(Cx² + Cy²)

And the direction of the resultant vector is:

θ = atan(Cy/Cx)

7 0

3 years ago

A portion of Nichrome wire of radius 2.50 mm is to be used in winding a heating coil. If the coil must draw a current of 9.25 A

Sedaia [141]

The resistance of the coil is 12. 97 Ω

<h3>How to determine the length</h3>

The formula for resistance is given as;

R = V/I

Note that resistance, R is measured in Ohms and represented with the symbol ( Ω)

Where;

V is the voltage = 120 V
I is the current = 9. 25 A

Substitute the values into the formula

R = 120/ 9. 25

R = 12. 97 Ω

The resistance, R is 12. 97 Ω

Hence, the resistance of the coil is 12. 97 Ω

Learn more about resistance here:

brainly.com/question/17563681

#SPJ4

5 0

2 years ago