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babymother [125]
3 years ago
12

Is NaCH a element?Why or why not?

Physics
2 answers:
sattari [20]3 years ago
8 0

Answer:

Explanation:

I don't think it is, but I do know that NaCI is an element. Hope this helps!

Arisa [49]3 years ago
8 0

Answer:

No, NaCH is not an element.

Explanation:

NaCH is a compound of several elements not just one.

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Keaton is asked to solve the following physics problem:
RideAnS [48]

Answer:

The answer is C "think about the problem first, systematically consider all factors, and form a hypothesis"

Explanation:

In physics there is some basic fomula that sir Isacc Newton proposed under the topic of motion. The three formulas are below;

<em>1) v=u+at</em>

<em>2)v^2=u^2+2as</em>

<em>3)s=ut+(1/2)(at^2)</em>

the variables are explained below;

u= initial velocity of the body

a=acceleration/Speed of the body

t= time taken by the body while travelling

s= displacement of the body.

Therefore to solve keatons problem, the factors(variables) in the formulas above need to be systematically considered. Since the ball was dropped from the top of the building, the initial velocity is 0 because the body was at rest. Also the acceleration will be acceleration due to gravity (9.8m/s^2)

5 0
3 years ago
Use the drop-down menus to complete the statement.
VashaNatasha [74]

Answer: A is your answer i am sorry if i am wrong

Explanation:

he first PLCs were programmed with a technique that was based on relay logic wiring schematics. This eliminated the need to teach the electricians, technicians and engineers how to program a computer - but, this method has stuck and it is the most common technique for programming PLCs today.

7 0
3 years ago
Read 2 more answers
Answer the question with step.​
Maru [420]

Answer:

f1/f2 =W1/W2 = 1/3

.0 f2 = 3f1

As ,

1/F= 1/f1 +1/f2

...1/40 = 1/f1 - 1/3f1

f1=> 80/3 cm

... f2 = 2f1 = 3 x 80/3 = 80 cm

7 0
3 years ago
At an accident scene on a level road, investigators measure a car’s skid mark to be 88 m long. The accident occurred on a rainy
Oduvanchick [21]

Answer:

The the speed of the car is 26.91 m/s.

Explanation:

Given that,

distance d = 88 m

Kinetic friction = 0.42

We need to calculate the the speed of the car

Using  the work-energy principle

work done = change in kinetic energy

W=\Delta K.E

\mu\ mg\times d=\dfrac{1}{2}mv^2

v^2=2\mu g d

Put the value into the formula

v=\sqrt{2\times0.42\times9.8\times88}

v=26.91\ m/s

Hence, The the speed of the car is 26.91 m/s.

3 0
3 years ago
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A sample of gas has a volume of 215 cm3 at 23.5 °c and 84.6 kpa. what volume (cm3 will the gas occupy at stp
Dafna11 [192]
The answer is 165.3 cm³.

P1 * V1 / T1 = P2 * V2 / T2

The initial sample:
P1 = 84.6 kPa
V1 = 215 cm³
T1 = 23.5°C = 23.5 + 273 K = 296.5 K

At STP:
P2 = 101.3 kPa
V2 = ?
T2 = 273 K

Therefore:
84.6 * 215 / 296.5 = 101.3 * V2 / 273
61.34 = 101.3 * V2 / 273
V2 = 61.34 * 273 / 101.3
V2 = 165.3 cm³
6 0
3 years ago
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