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3 years ago

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Describe the motion for each segment below. Include start position, relative speed, and direction. Then calculate the speed of e

ach section. Finally, write the equation of the line segment for segment C.

1 answer:

ratelena [41]3 years ago

3 0

Where is the picture?

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Elena pulls a sled with her younger brother and sister across the snow covered yard. Then she pulls the same sled across a smoot

mylen [45]

The answer is B.
Hope this helps!

5 0

3 years ago

Please help me with this (with explanation)

Sergeeva-Olga [200]

Suppose the cyclist travels for a total time of <em>t</em> hours.

For 20 min = 1/3 hr, the cyclist does not move.

Over the remaining (<em>t</em> - 1/3) hr, the cyclist is moving at a constant speed of 22.0 km/hr, so that the cyclist would travel a distance of

<em>x</em> = (22.0 km/hr) • ((<em>t</em> - 1/3) hr) ≈ (22.0 km/hr) <em>t</em> - 7.33 km

If the cyclist's average speed over the total time <em>t</em> was 17.5 km/hr, then by the definition of average speed,

17.5 km/hr = <em>x</em> / <em>t</em>

Replace <em>x</em> with the distance expression from earlier:

17.5 km/hr = ((22.0 km/hr) <em>t</em> - 7.33 km) / <em>t</em>

Solve for <em>t</em> :

17.5 km/hr = 22.0 km/hr - (7.33 km) / <em>t</em>

(7.33 km) / <em>t</em> = 4.5 km/hr

<em>t</em> = (7.33 km) / (4.5 km/hr)

<em>t</em> ≈ 1.62963 hr

Then the distance the cyclist traveled must have been

<em>x</em> ≈ (22.0 km/hr) (1.62963 hr) - 7.33 km ≈ 28.5 km

and so the answer is A.

Alternatively, as soon as you arrive at

17.5 km/hr = <em>x</em> / <em>t</em>

you can instead solve for <em>t</em> in terms of <em>x</em>, then plug that into the distance equation.

<em>t</em> = <em>x</em> / (17.5 km/hr)

then

<em>x</em> ≈ (22.0 km/hr) (<em>x</em> / (17.5 km/hr)) - 7.33 km

<em>x</em> ≈ 1.25714 <em>x</em> - 7.33 km

0.25714<em>x</em> ≈ 7.33 km

<em>x</em> = (7.33 km) / 0.25714 ≈ 28.5 km

6 0

3 years ago

Hooke’s law states that the distance that a spring is stretched by hanging object varies directly as the mass of the object. If

trasher [3.6K]

Answer:

$d_{2}$ = 33.33 cm

Explanation:

Given:

When mass, $m_{1}$ =21 kg

distance travelled is $d_{1}$ = 140 cm

When mass, $m_{2}$ =5 kg

distance travelled is $d_{2}$ = ?

Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.

Therefore according to the question,

$\frac{d_{1}}{m_{1}}=\frac{d_{2}}{m_{2}}$

$\frac{140}{21}=\frac{d_{2}}{5}$

$d_{2}$ = 33.33 cm

Distance travelled is 33.33 cm when mass is 5 kg.

8 0

3 years ago

Technician A says that vehicle-to-vehicle communication results in fewer traffic collisions. Technician B says there are concern

Leto [7]

Answer:

Option C. Both technicians A and B are correct

Explanation:

Vehicle-to-vehicle communications consists of a wireless network where automobiles send messages containing operational information such as speed, location, direction of travel, braking, and loss of stability.

Technician A is correct, there will be fewer traffic collision because each driver will have enough information about traffic flow and such information will be properly managed since they have been known before hand.

By letting out information, such as your location, direction of traffic, etc, there is loss of privacy. This can lead to a security threat on the part of the users

4 0

3 years ago

A Blu-ray disk spins up from rest to an angular speed of about 10,000 revolutions per minute. If it

erma4kov [3.2K]

The correct answer is B 5,000 rev/s^2

4 0

3 years ago