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3 years ago

According to Huygens's principle, what is the explanation for boundary behaviors?

Physics

2 answers:

max2010maxim [7]3 years ago

4 0

A.) Each point on a wave front acts as a source of secondary waves.

Alex787 [66]3 years ago

3 0

Answer:

A.) Each point on a wave front acts as a source of secondary waves.

Explanation:

Huygen's principle can explain some phenomena such as the diffraction of light through a single or a double slit, and the interference pattern that we see on the screen. In fact, according to Huygen's principle, each point of the wave front inside the gap in the slit acts as a source of secondary waves: therefore, we can imagine all the points inside the slit as sources of secondary waves, and these waves interact with each other producing interference, and this is why we observe an interference pattern on the screen.

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A child sleds down a hill with an acceleration of 2.94 m/s2. If her initial speed is 0.0 m/s and her final speed is 17.5 m/s, ho

hram777 [196]

Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial ( $v_{o}$ ) and final speeds ( $v_{f}$ ), measured in meters per second, and acceleration ( $a$ ), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom ( $t$ ), measured in seconds, is:

$t = \frac{v_{f}-v_{o}}{a}$ (1)

If we know that $v_{o} = 0\,\frac{m}{s}$ , $v_{f} = 17.5\,\frac{m}{s}$ and $a = 2.94\,\frac{m}{s^{2}}$ , then the time taken is:

$t = \frac{17.5\,\frac{m}{s}-0\,\frac{m}{s} }{2.94\,\frac{m}{s^{2}} }$

$t = 5.952\,s$

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

8 0

3 years ago

A constant force of 20. newtons applied to a box causes it to move at a constant speed of 4.0 meters per second. How much work i

podryga [215]

The answer is 3) 480 joules

6 0

2 years ago

What is a measure of the amount of matter in an object? Question 2 options: Force Inertia Mass Acceleration

fredd [130]

The answer is C.) mass is the matter of an object

6 0

3 years ago

Read 2 more answers

not all objects have a volume that is measured easily. If you were to determine the mass, volume, and density of your textbook,

Maslowich

Text book: We can measure the mass of the text book easily by weighing machine, to measure the volume we need to measure the length, width, and height of the text book by the ruler, by multiplying these dimension we can get the volume of the text book, and by dividing the mass of the book with its volume we can get the density of the book.

Milk Container: We can measure the mass of the milk container easily by weighing machine, now (assuming the milk container is cylindrical in shape) we need to measure its height, and and diameter and by the formula (π*r^2*h) we can measure its volume, and and by dividing the mass with its volume we can get the density of the milk container.

Air filled balloon: we can measure the mass of the air filled balloon by weighing it weight machine, we know that the density of air is 28.97 kg/m^3, by dividing the mass of the balloon with the denisty of air we can get the volume of the balloon.

3 0

3 years ago

Read 2 more answers

A 1350 kg uniform boom is supported by a cable. The length of the boom is l. The cable is connected 1/4 the

olchik [2.2K]

Answer:

Tension= 21,900N

Components of Normal force

Fnx= 17900N

Fny= 22700N

FN= 28900N

Explanation:

Tension in the cable is calculated by:

Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium

FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)

Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)

Ftorque= 2/3FBcostheta+ 4/3FWcostheta

Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°

Ftorque= 21900N

b) components of Normal force

Efx=FNx-FTcos(90-theta)=0 static equilibrium

Fnx=21900cos(90-55)=17900N

Fy=FNy+ FTsin(90-theta)-FB-FW=0

FNy= -FTsin(90-55)+FB+FW

FNy= -21900sin(35)+(1350+2250)×9.81=22700N

The Normal force

FN=sqrt(17900^2+22700^2)

FN= 28.900N

4 0

3 years ago