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2 years ago

According to Huygens's principle, what is the explanation for boundary behaviors?

Physics

2 answers:

max2010maxim [7]2 years ago

4 0

A.) Each point on a wave front acts as a source of secondary waves.

Alex787 [66]2 years ago

3 0

Answer:

A.) Each point on a wave front acts as a source of secondary waves.

Explanation:

Huygen's principle can explain some phenomena such as the diffraction of light through a single or a double slit, and the interference pattern that we see on the screen. In fact, according to Huygen's principle, each point of the wave front inside the gap in the slit acts as a source of secondary waves: therefore, we can imagine all the points inside the slit as sources of secondary waves, and these waves interact with each other producing interference, and this is why we observe an interference pattern on the screen.

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The advantage of a fixed pulley on a flag pole is that it ___________.(1 point)

umka2103 [35]

Decreases the input force

6 0

2 years ago

In a series RLC ac circuit, a second resistor is connected in series with the resistor previously in the circuit. As a result of

AnnyKZ [126]

Answer:

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

Z = R + R₂

Explanation:

The impedance of a series circuit is

Z₀² = R² + (X_L-X_C) ²

when we place another resistor in series the initial resistance impedance changes to

Z² = (R + R₂) ² + (X_L - X_C) ²

let's analyze this expression

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

Z = R + R₂

8 0

2 years ago

A 4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. What is the diameter of t

sladkih [1.3K]

Explanation:

Given that,

Length of gold wire, l = 4 m

Voltage of battery, V = 1.5 V

Current, I = 4 mA

The resistivity of gold, $\rho=2.44\times 10^{-8}\ \Omega-m$

Resistance in terms of resistivity is given by :

$R=\dfrac{\rho l}{A}$

Also, V = IR

So,

$\dfrac{V}{I}=\dfrac{\rho l}{A}$

A is area of wire,

$\dfrac{V}{I}=\dfrac{\rho l}{\pi r^2}$ , r is radius, r = d/2 (diameter=d)

$\dfrac{V}{I}=\dfrac{\rho l}{\pi (d/2)^2}\\\\\dfrac{V}{I}=\dfrac{4\rho l}{\pi d^2}\\\\d=\sqrt{\dfrac{4\rho l I}{V\pi}} \\\\d=\sqrt{\dfrac{4\times 2.44\times 10^{-8}\times 4\times 4\times 10^{-3}}{1.5\times \pi}} \\\\d=18.2\ \mu m$

Out of four option, near option is (C) 17 μm.

6 0

2 years ago

A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light supporting cable

kompoz [17]

Answer:

4.44s

Explanation:

A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light supporting cables for the swing is 4.9 m, how long does it take for each complete back-and-forth swing? Assume that the child and swing set are very small compared to the length of the cables

since the mass of the child and that of the swing is negligible, the masses wont be involved in the calculation

T=2π√L/g

g=acceleration due to gravity which is 9.81m/s2

the length of the supporting cable is 4.9m

T the period

period is the time required to make a complete oscillation

T=2*π√4.9/9.81

T=2*π*0.706

T=4.44s

4.44s

5 0

2 years ago

qué le sucede a la intensidad de la luz de cada bombillo en un circuito en serie si agregas más bombillos al circuito?

aalyn [17]

La intensidad de la luz se baja con cada bombillo que agregas

7 0

2 years ago