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nikdorinn [45]
3 years ago
13

According to Huygens's principle, what is the explanation for boundary behaviors?

Physics
2 answers:
max2010maxim [7]3 years ago
4 0
A.) Each point on a wave front acts as a source of secondary waves.
Alex787 [66]3 years ago
3 0

Answer:

A.) Each point on a wave front acts as a source of secondary waves.

Explanation:

Huygen's principle can explain some phenomena such as the diffraction of light through a single or a double slit, and the interference pattern that we see on the screen. In fact, according to Huygen's principle, each point of the wave front inside the gap in the slit acts as a source of secondary waves: therefore, we can imagine all the points inside the slit as sources of secondary waves, and these waves interact with each other producing interference, and this is why we observe an interference pattern on the screen.

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4. Choose the velocity quantity from the following.
Tresset [83]

Answer:

a.8m/s is my ans it may help you

3 0
3 years ago
Explain the difference between displacement and distance
alisha [4.7K]
<span>Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.</span>
6 0
3 years ago
To make a given sound seem twice as loud, how should a musician change the intensity of the sound?
Serhud [2]

Answer:

C. Quadruple the intensity

Explanation:

The intensity of the sound is proportional to square of amplitude of the sound.

I ∝ A²

\frac{I_1}{A_1^2} = \frac{I_2}{A_2^2}\\\\I_2 = \frac{I_1A_2^2}{A_1^2}

When the given sound is twice loud as the initial value, then the new amplitude is twice the former.

A₂ = 2A₁

I_2 = \frac{I_1A_2^2}{A_1^2} \\\\I_2 = \frac{I_1(2A_1)^2}{A_1^2} \\\\I_2 = \frac{4I_1A_1^2}{A_1^2}\\\\ I_2 = 4I_1

Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity

3 0
3 years ago
Who was the first to hypothesize that electron orbit a positively charged nucleus
Eva8 [605]
I think the answer is ruthorford
6 0
3 years ago
A guitar string is 0.620m long, and oscillates at 234Hz. What is the velocity of the waves in the string? m/s
9966 [12]

Answer:

v = 72.54 m/s

Explanation:

We have,

Length of a guitar string is 0.62 m

Frequency of a guitar string is 234 Hz

For guitar string,

L=2\lambda\\\\\lambda=\dfrac{L}{2}\\\\\lambda=\dfrac{0.62}{2}\\\\\lambda=0.31\ m

The velocity of the wave in the string is given by :

v=f\lambda\\\\v=234\times 0.31\\\\v=72.54\ m/s

So, the velocity of the waves in the string is 72.54 m/s.

3 0
3 years ago
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