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Ivenika [448]
2 years ago
14

A variable that is kept the same through the experiment to make the test fair

Chemistry
1 answer:
sveta [45]2 years ago
3 0
It would be the controlled variable, which is a baseline to compare your other variables too.

Hope this helps!
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12 moles are in the 175L of SO2 gas at STP
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The US mail delivery considered a network true or false
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6 0
2 years ago
Determine the grams of protein in one cup of soup that has 140 kcal with 8 g of carbohydrate and 2 g of fat.
irina [24]

There are 22.5 grams of protein in one cup of soup that has 140 kcal with 8 g of carbohydrate and 2 g of fat.

<h3>What is the mass of a substance?</h3>

The mass of a substance is the quantity of the substance that is being measured in grams or kilograms.

To determine the energy from the 8g of carbohydrate, we have:

= 8g × 4 kcal/g (the corresponding calories of food type)

= 32 kcal

The energy from 2g of fat = 2g × 9 kcal/g

= 18 kcal

The energy from protein is calculated as:

= 140 kcal - 32 kcal - 18 kcal

= 90 kcal

The required mass of the protein in grams is:

\mathbf{= 90 \ kcal \times \dfrac{1}{4 \  kcal }}

= 22.5 grams

Therefore, we can conclude that there are 22.5 grams of protein in one cup of soup.

Learn more about the mass of a substance here:

brainly.com/question/837939

#SPJ1

7 0
1 year ago
What would be the best item to fill the cylinders with to measure the volume
Tpy6a [65]

Answer:

Most accurate glassware for measuring volume

Graduated cylinders, beakers, volumetric pipets, burets and volumetric flasks are five kinds of glassware often used to measure out specific volumes. Volumetric pipets, flasks and burets are the most accurate; the glassware makers calibrate these to a high level of accuracy.

Explanation:

6 0
3 years ago
How much energy is needed to vaporize 75.0 g of diethyl ether (c4h10o) at its boiling point (34.6°c), given that δhvap of diethy
malfutka [58]

Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

Explanation:

First we have to calculate the moles of diethyl ether

\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles

As, 1 mole of diethyl ether require heat = 26.5 kJ

So, 1.01  moles of diethyl ether require heat = \frac{26.5}{1}\times 1.01=26.8kJ

Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

5 0
3 years ago
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