Answer:
476.387 Hz
714.583 Hz
Explanation:
L = Length of tube
v = Speed of sound in air = 343 m/s
Frequency for a closed tube is given by

The frequency is 476.387 Hz
If it was one third full 

The frequency is 714.583 Hz
B. It has membrane-bound organelles.
This is the most logical choice. For example, rocks can be found in water AND possess uneven shapes.
Answer:
The magnitude of the electric field are
and 
Explanation:
Given that,
Radius of inner shell = 11.0 cm
Radius of outer shell = 14.0 cm
Charge on inner shell 
Charge on outer shell 
Suppose, at r = 11.5 cm and at r = 20.5 cm
We need to calculate the magnitude of the electric field at r = 11.5 cm
Using formula of electric field

Where, q = charge
k = constant
r = distance
Put the value into the formula


The total charge enclosed by a radial distance 20.5 cm
The total charge is

Put the value into the formula


We need to calculate the magnitude of the electric field at r = 20.5 cm
Using formula of electric field

Put the value into the formula


Hence, The magnitude of the electric field are
and 
Answer:
They would decline
Explanation:
They would either migrate, or die.
Answer:
The terrestrial planets are closer to the sun.
Explanation: