All categories

3 years ago

A bird carries a 25 g oyster to a height of 11m what is the gravitational potential energy of the oyster

Physics

1 answer:

garik1379 [7]3 years ago

7 0

Given data:

Mass of oyster (m) = 25 g,

= 0.025 kg ( since 1 Kg = 1000 g)

Height of oyster (h) = 11 m,

determine gravitational potential energy (GPE) = ?

Gravitational potential energy is energy of an object possesses because of its position on the earth. The amount of gravitational potential energy of an object on earth depends on its mass and height from the earth.

Mathematically,

GPE = m. g. h Joules

Where,

GPE = gravitational potential energy,

m = mass of object in Kg,

g = gravitational force in m/s², g = 9.8 m/s²

h = height of the object in meters,

Now substituting all the values in the equation GPE

GPE = 0.025 Kg × 9.8 m/s² × 11 m

= 2.695 J

Gravitational potential energy of the oyster is 2.695 J

You might be interested in

Mass m, moving at speed 2v, approaches mass 4m, moving at speed v. The two collide elastically head-on. Part A Find the subseque

meriva

Thank you for posting your question here at brainly. A mass of m moves with 2V towards in the opposite direction of a mass, 4m moving at a speed of V, the speed of m was 2/5V and the mass of 4m was 7.5V. I hope it helps.

4 0

3 years ago

Read 2 more answers

PLEASE HELP!! DUE SOON!!!

max2010maxim [7]

Answer:

See attached file :)

Hope this helps!

All the love, Ya boi Fraser :)

4 0

2 years ago

Read 2 more answers

Darwin believed that emotional expressions began as ________ that came to have evolutionary value because they ________. Select

Strike441 [17]

Answer:

c. physiological reactions; convey emotional states to other members of the species

Explanation:

Darwin believed that emotional expressions began as physiological reactions that came to have evolutionary value because they convey emotional states to other members of the species. These reactions are used by many different types of species to convey various things.

5 0

2 years ago

A jogger runs 4.0 km [W] in 0.50 h, then turns and runs 1.0 km [E] in 0.20 h, then 1.5 km [N] in 0.25 h, then 3.0 km [E] in 0.75

GrogVix [38]

This is a sneaky trick question, to help you discover whether you know
one of the differences between velocity and speed.
=======================================
If you make a list of the distances and directions, and ignore the times,
you find these:

4 - west, (3 + 1) - east . . . . . zero in the east/west direction

1.5 - north, 1.5 - south . . . . . zero in the north/south direction

This jogger went out, had a nice jog around the neighborhood,and ended up exactly where he started.

Average velocity = (distance between start point and end point) / (time)

IF the question asked for average SPEED, then you would need the total distance, and divide it by the total time. But it asks for VELOCITY, and that only involves the straight distance between the start point and the end point, regardless of the route taken in between.

The jogger ended up exactly where he started. The distance between start and end points was zero. Average velocity is (zero) / (time) . And that fraction is going to be Zero, no matter how long or how short the trip was, and no matter how much time it took.

3 0

3 years ago

Read 2 more answers

A uniform solid cylinder of radius r and mass m can roll inside a hollow cylinder of radius R > r without slipping. A pendulu

iogann1982 [59]

Answer: The two answers are in explanation.

Explanation: Please find the attached files for the solution

8 0

3 years ago