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VLD [36.1K]
3 years ago
15

99 POINTS Which volcanoes are the tallest Shield, Cinder Cones or Composite Cones?

Chemistry
2 answers:
charle [14.2K]3 years ago
6 0
Shield volcanos are the tallest. The tallest one is Mauna Loa in Hawaii
zhenek [66]3 years ago
3 0
The guy is right at the top 
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Calculate the molar mass of CH4 gas at STP when 5.46Lof the gas weighs 4g??​
meriva

Answer:

About 16.42 grams

Explanation:

PV=nRT \\\\(1)(5.46L)=n(0.0821)(273) \\\\n\approx 0.2436 \\\\4g/0.2436\approx 16.42

Hope this helps!

6 0
3 years ago
The mass of cupric sulfate needed to make .5 liters of a .5M solution is
dalvyx [7]

Answer:

C

Explanation:

3 0
3 years ago
Trace amounts of sulfur (S) in coal are burned in the presence of diatomic oxygen (O2) to form sulfur dioxide (SO2). Determine t
Mashcka [7]

Answer:

0.99 kg O₂

1.9 kg SO₂

Explanation:

Let's consider the reaction between sulfur and oxygen to form sulfur dioxide.

S + O₂ → SO₂

The mass ratio of S to O₂ is 32.07:32.00. The mass of oxygen required to react with 1 kg of sulfur is:

1 kg S × (32.00 kg O₂/32.07 kg S) = 0.998 kg O₂

The mass ratio of S to SO₂ is 32.07:64.07. The mass of sulfur dioxide formed when 1 kg of sulfur is burned is:

1 kg S × (64.07 kg SO₂/32.07 kg S) = 1.99 kg SO₂

3 0
3 years ago
isotopes of an element have the same number of protons but a different number of neutrons below u will see the nucleus of four d
dexar [7]
What is your question? Its not clear
3 0
3 years ago
How many moles of gas are in a 1.0 liter canister if the temperature of the canister is 100 K and the pressure is 100 atmosphere
ladessa [460]

Answer:

n = 12.18 moles

Explanation:

Given that,

The volume of a canister, V = 1 L

The temperature of the canister, T = 100 K

Pressure, P = 100 atm

We need to find the number of moles of gas. Let there are n number of moles. We know that,

PV = nRT

Where

R is gas constant, R = 0.0821 L*atm/mol*K

n=\dfrac{PV}{RT}\\\\n=\dfrac{100\times 1}{0.0821 \times 100}\\\\n=12.18\ moles

Hence, there are 12.18 moles of gas.

4 0
3 years ago
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