Answer:
a. -7.44 °C
Explanation:
Hello there!
In this case, since the freezing point depression formula is:
Thus, since the Van't Hoff's factor is 2 for KCl as it ionizes in K⁺ and Cl⁻, the molarity is 2.0 m (2.0mol/1.0kg) and the freezing point depression constant is 1.86 °C/m, we calculate the freezing point depression as follows:
Therefore, the answer is a. -7.44 °C.
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Answer:
The answer to your question is: letter E, 1.77 L of 1.55 M Ba(NO3)2
Explanation:
Formula
Molarity =
moles = Molarity x volume (L)
a. 2.58 L of 0.0250 M Ba(NO3)2
moles = (0.025) (2.58)
moles = 0.065 M
b. 19.23 mL of 8.5 × 10−2 M Ba(NO3)2
moles = (8.5 x 10 ⁻²) (0.01923)
moles = 0.0016
c. No right answer.
d. 26.20 mL of 2.21 M Ba(NO3)2
moles = (2.21)(0.0262)
moles = 0.058
e. 1.77 L of 1.55 M Ba(NO3)2
moles = (1.55)(1.77)
moles = 2.74 This solution needs the greatest concentration of
Ba(NO₃)₂