3 years ago

PLEASE HURRY NEED ASAP

Physics

1 answer:

daser333 [38]3 years ago

3 0

I THINK THIS IS THOUGHTS AND FEELINGS

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One mole of water is equivalent to 18 grams of water. A glass of water has a mass of 200 g. How many moles of water is this?

Black_prince [1.1K]

200g*1 mole/ 18g=11.1 moles There are 11.1 moles of water.

4 0

3 years ago

Read 2 more answers

What did the Federal Highway Act do?

saw5 [17]

Answer:

Explanation:

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3 years ago

Light of wavelength 559 nm is used to illuminate normally two glass plates 22.1 cm in length that touch at one end and are separ

umka21 [38]

Answer:

M = 222 fringes

Explanation:

given

λ = 559 n m = 559 × 10⁻⁹ m

radius = 0.026 mm = 0.026 ×10⁻³ m

length of the glass plate = 22.1 ×10⁻² m

using relation

$2t=(m+\dfrac{1}{2})\lambda\ \ (m=0,1,2,3...)\\where\ 0\leq t\leq 2r\\m = \dfrac{2t}{\lambda}-\dfrac{1}{2}$

$m_{max} = \dfrac{2\times 2r}{\lambda}-\dfrac{1}{2}\\m_{max} = \dfrac{2\times 2\times 0.026\times 10^{-3}}{559\times 10^{-9}}-\dfrac{1}{2}$

= 221.79

= 221 (approx.)

hence no of bright fringe

M = m + 1

= 221 +1

M = 222 fringes

6 0

3 years ago

A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located

nadezda [96]

Answer:

$\Delta V = 30V$

Explanation:

give data:

inside diameter = 5.0 cm

charge q = 0.25 nC

Outside diameter = 15 cm

potential V at inside sphere is = $V=\frac{kq}{R}$

potential V at outside sphere is = $V=\frac{kq}{r}$

k is constant whose value is = $8.99 *10^{9}Nm^{2}/c^2$

then potential difference between two point is

$\Delta V = kq \left [\frac{1}{R}-\frac{1}{r} \right ]$

$\Delta V = 9*10^{9}*0.25*10^{-9} \left [\frac{1}{0.05}-\frac{1}{0.15} \right ]$

$\Delta V = 30V$

6 0

4 years ago

A crate is to be pulled across the floor. The crate will experience a force of friction of 34 N. You pull on the crate with a fo

Jobisdone [24]

The net force would be 75N - 34N = 41N

The crates rate of acceleration would be 41N=8.5*a so a = 4.8m/s^2

6 0

3 years ago