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olga_2 [115]
3 years ago
5

PLEASE HURRY NEED ASAP

Physics
1 answer:
daser333 [38]3 years ago
3 0
I THINK THIS IS THOUGHTS AND FEELINGS
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Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. T
diamong [38]

Answer:

Rate of heat is 45.1 kJ/min

Explanation:

Heat required to evaporate the water is given by

Q = mL

here we know that

L = 2.25 \times 10^6 J/kg

now we have

Q = (0.200)(2.25 \times 10^6 J/kg)

Q = 452.1 kJ

now the power is defined as rate of energy

P = \frac{Q}{t}

P = \frac{452.1 kJ}{10}

P = 45.1 kJ/min

6 0
3 years ago
3. Ecology
Korvikt [17]

Answer:

The family would not have hot water unless they were to heat the the water. They would have to depend on the stove in order to survive by heating the house to say alive and not freeze. They would also have to depend on the stove to get hot water to do any, but if the sun goes away for too long and everything starts to die then they will have to use what food and wood that they have in order to survive.

Explanation:

6 0
3 years ago
What is the difference between current electricity and static electricity
Allisa [31]

Answer:

The most significant difference between the static and current electricity is that in static electricity the charges are at rest and they are accumulating on the surface of the insulator. Whereas in current electricity the electrons are moving inside the conductor.

7 0
3 years ago
Read 2 more answers
After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38
ddd [48]

Answer:

64.2 m/s

Explanation:

We are given that

Speed ,v=38 m/s

We have to find the maximum speed when his car reach on flat ground.

Using dimensional analysis

F_{res}\propto v^2

If 35% acceleration reduced by F(res) at 38 m/s

Then, 100% acceleration  can be reduced  by F(res) at v' m/s

\frac{F_1}{F_2}=\frac{v^2}{v'^2}

v'^2=\frac{F_2}{F_1}v^2

v'=v\sqrt{\frac{F_2}{F_1}}

Substitute the values

v'=38\times \sqrt{\frac{100}{35}}

v'=64.2 m/s

Hence, the maximum speed when his car can reach on flat ground=64.2 m/s

3 0
3 years ago
A plank rests on top of the axles of two identical wheels. Each wheel's outer radius is 0.25 meters and each wheel's axle has ra
kaheart [24]

Answer:

<u><em>The plank moves 0.2m from it's original position</em></u>

Explanation:

we can do this question from the constraints that ,

  • the wheel and the axle have the same angular speed or velocity
  • the speed of the plank is equal to the speed of the axle at the topmost point .

thus ,

<em>since the wheel is pure rolling or not slipping,</em>

<em>⇒v=wr</em>

where

<em>v - speed of the wheel</em>

<em>w - angular speed of the wheel</em>

<em>r - radius of the wheel</em>

<em>since the wheel traverses 1 m let's say in time 't' ,</em>

<em>v_{w}=\frac{distance}{time} =\frac{1}{t}</em>

∴

⇒w=\frac{v_{w}}{r} = \frac{1}{t*0.25}

the speed at the topmost point of the axle is :

⇒v_{a}=w*r\\v_{a}=\frac{1}{t*0.25} *0.05\\v_{a}=\frac{1}{5t}

this is the speed of the plank too.

thus the distance covered by plank in time 't' is ,

⇒d=v_{a}*t\\d=\frac{1}{5t} *t\\d=\frac{1}{5} = 0.2m

8 0
3 years ago
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