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jeka94
3 years ago
15

A production plant has a requirement for a counter that will count 4,000 items before recycling and starting over. How many D fl

ip-flop stages would be required in this counter
Engineering
1 answer:
k0ka [10]3 years ago
6 0

Answer:

12

Explanation:

A n-bit integer represents values from 0 to (2^n)-1 states. For example, if we have 3 bits we can count up to 7 states, that is counting from 0 to 7.

On the other hand, a flip flop stores one bit of data  So, we will need n flip flops to count (2^n) -1 states.

So we have production plant that requires a counter that will count 4,000 items before recycling and starting over.

Therefore (2^n) - 1 =4000. The nearest integer value of n that will give 4000 is 12.

For n = 12 , 2^12 = 4096 and for n =11 2^11 = 2048. 12 is the closest value. Therefore we need 12 D Flip Flop stages to count the required items.

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Problem 4.041 SI Refrigerant 134a enters an insulated compressor operating at steady state as saturated vapor at -26oC with a vo
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Answer:

0.0297M^3/s

W=68.48kW

Explanation:

Hello! To solve this problem, we must first find all the thermodynamic properties at the input (state 1) and the compressor output (state 2), using the thermodynamic tables

Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  

state 1

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T=-26C

density 1=α1=5.27kg/m^3  

entalpy1=h1=234.7KJ/kg

state 2

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density 2=α2=31.91kg/m^3  

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Now to find the flow at the outlet of the compressor, we remember the continuity equation that states that the mass flow is equal to the input and output.

m1=m2

(Q1)(α1)=(Q2)(α2)

\frac{(Q1)(\alpha 1) }{\alpha 2} =Q2\\Q2=\frac{(0.18)(5.27) }{31.91} =0.0297M^3/s

the volumetric flow rate at the exit is 0.0297M^3/s

To find the power of the compressor we use the first law of thermodynamics that says that the energy that enters must be equal to the energy that comes out, in this order of ideas we have the following equation

W=m(h2-h1)

m=Qα

W=(0.18)(5.27)(306.9-234.7)

W=68.48kW

the compressor power is 68.48kW

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