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Brut [27]
3 years ago
14

What are the cellulose and ligin are changed int other substances

Chemistry
1 answer:
slava [35]3 years ago
3 0
WAit I just have one tiny little question did your mom dad grandma grandpa helpful I with the question first
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Which 4 elements make up the bulk of living matter?
Hitman42 [59]
"<span>Let's start with the basics:  you have probably heard that your body is 90% (or 85% or 95%) water.  In actual fact, water is (probably--unless you are obese) the majority of your body weight--but nowhere near 90%.  The best estimate I have seen is 57% (Body water).  So that puts hydrogen and oxygen in the top four.
 
As I mentioned, extremely obese people can be less than 50% water.  Fat (triglycerides) is composed of carbon, hydrogen, and oxygen.  The majority of the mass of a triglyceride is carbon--chemically it is closely related to biodiesel.  So that puts carbon in the top four.
 
Finally, amino acids which make up proteins (which make up muscle) require nitrogen.  That makes the top four.:  Oxygen, Carbon, Hydrogen, and Nitrogen.
 
But wait!  What about bones?  Aren't they calcium and phosphorous?  Bones are really heavy. 
 
It turns out that calcium and phosphorous are indeed the next two most abundant (by mass) elements in the body, but where nitrogen is about 3% of your body mass, calcium and phosphorous are 1.5% and 1.2% respectively. 
 
You can find the full breakdown of the elemental composition of your body here: <span>Abundance of the chemical elements"

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4 0
3 years ago
Aqueous hydrochloric acid HCl reacts with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H
allochka39001 [22]

Answer : The theoretical yield of water formed from the reaction is 0.54 grams.

Solution : Given,

Mass of HCl = 1.1 g

Mass of NaOH = 2.1 g

Molar mass of HCl = 36.5 g/mole

Molar mass of NaOH = 40 g/mole

Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of HCl and NaOH.

\text{ Moles of }HCl=\frac{\text{ Mass of }HCl}{\text{ Molar mass of }HCl}=\frac{1.1g}{36.5g/mole}=0.030moles

\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{2.1g}{40g/mole}=0.525moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NaOH

So, 0.030 mole of HCl react with 0.030 mole of NaOH

From this we conclude that, NaOH is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2O

From the reaction, we conclude that

As, 1 mole of HCl react to give 1 mole of H_2O

So, 0.030 moles of HCl react to give 0.030 moles of H_2O

Now we have to calculate the mass of H_2O

\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O

\text{ Mass of }H_2O=(0.030moles)\times (18g/mole)=0.54g

Therefore, the theoretical yield of water formed from the reaction is 0.54 grams.

6 0
3 years ago
An ideal gas cannot exist outside of ideal gas conditions<br><br> true or false ?
zzz [600]

Answer:

Yes

Explanation:

5 0
2 years ago
Suppose you wanted to monitor a pH change between 5.3 and 6.3. Which indicator would be most appropriate?
umka2103 [35]
It would be acidic based indicator.
0-6 is acidic
7 is neutral 
8-14 is alkaline
7 0
3 years ago
Read 2 more answers
A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and
vladimir2022 [97]

Answer:

C_{7} H_{5}N_{3}O_{6}

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC

0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\

Analogously for hydrogen:

0.0310gH_{2}O have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N

now

\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}

and you can multiply by  5   to obtain: C_{7} H_{5}N_{3}O_{6}

4 0
3 years ago
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