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WARRIOR [948]
3 years ago
9

The sparse area surrounding a galaxy is called its ______________.

Physics
1 answer:
photoshop1234 [79]3 years ago
6 0
The sparse area surrounding a spiral galaxy is called its halo. Hoped this helped!
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A: receives information

B: Carries information away from the cell body

C: Delivers information to the next cell

Explanation:

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What kinds of information does the ALMA radio telescope provide?
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ALMA is a trans-formative radio telescope that can study cosmic light that straddles the boundary between radio and infrared. Most objects in the Universe emit this kind of energy, so the ability to detect it has been a driver for astronomers for decades.

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Lesson 1, What is Physical Science.
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Physical science explains the physical world and not supernatural events and an idea is considered true by science if it can be observed, explained and reproduced by others.

<h3>What is physical science?</h3>

Physical science is a systematic study of the of the physical world and phenomena based on observation and experiments.

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Science do not study about angels or demons or supernatural events.

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2 years ago
(Please help 15 points the assignment is late) (multiple questions) (everything is virtual task )
krok68 [10]

Answer:

i & 2

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U alr finished it so there's no point

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2 years ago
Youare on a train travelling northat 80.0m/s relative to the ground. The air is still relativetothegroundwhen you hear the whist
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To solve this problem we will apply the concepts related to the Doppler effect. This is understood as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically this is given as,

f = \frac{v \pm v_r}{v \pm v_s}(f_0)

Here,

v = Speed of the waves in the middle

v_r = Speed of the receiver in relation to the medium (Positive if the receiver is moving towards the transmitter or vice versa)

v_s = Speed of the source with respect to the medium (Positive if the source moves away from the receiver or vice versa)

Our values are given as,

v = 342m/s

f_0 = 262Hz

v_r = 80m/s

f = 350Hz

Replacing,

350 = \frac{342+80}{342-v} (262)

Solving for the velocity of the source,

v = 26.1m/s

Therefore the speed of the other train is 26.1m/s

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2 years ago
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