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Likurg_2 [28]
3 years ago
5

A capacitor consists of a set of two parallel plates of area A separated by a distance d . This capacitor is connected to a batt

ery that maintains a constant potential difference V across the plates. If the separation between the plates is doubled, the electrical energy stored in the capacitor will be
Physics
1 answer:
Elis [28]3 years ago
5 0

Answer:

if we double the distance the energy stored will be doubled also

Explanation:

The energy stored in a capacitor is given as

Energy stored =1/2(cv²)

Or

= 1/2(Qv)

Where c = capacitance

Q= charge

But the electric field is expressed as

E= v/d

where v= voltage

d= distance

v=Ed

Substituting into any equation above say

Energy stored =1/2(Qv)

Substituting v=Ev

Energy stored =1/2(QEd)

From the equation above it shows that if we double the distance The energy stored will be doubled also

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What type of wave is shown below?
Elena-2011 [213]

Answer:

<u>B</u><u>.</u><u> </u><u>Transverse</u><u> </u><u>wave</u><u>.</u>

Explanation:

Because it has troughs and crests.

5 0
3 years ago
What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?
Akimi4 [234]
2(3x - 1) ≥ 4x - 6  Remove the brackets on the left.
6x - 2  ≥ 4x - 6     Subtract 4x from both sides.
6x - 4x - 2 ≥ - 6    combine like terms on the left.
2x - 2 ≥ - 6           Add 2 to both sides
2x ≥ - 6+ 2
2x ≥ -4                 Divide by 2
x ≥ - 4/2
x ≥ - 2  answer <<<<<<<<

Check
2(3*-2 - 1) ≥ 4x - 6
2(-6 - 1) ≥ 4(-2) - 6
2(-7) ≥- 8 - 6
- 14 = - 14 and this checks.

4 0
3 years ago
From a vantage point very close to the track at a stock car race, you hear the sound emitted by a moving car. You detect a frequ
Alexandra [31]

Approximately 15 m/s is the speed of the car.

<u>Explanation:</u>

<u>Given:</u>

speed of sound - 343 m/s

You detect a frequency that is 0.959 times as small as the frequency emitted by the car when it is stationary. So, it can be written as,

f^{\prime}=0.959 f

\frac{f^{\prime}}{f}=0.959

If there is relative movement between an observer and source, the frequency heard by an observer differs from the actual frequency of the source. This changed frequency is called the apparent frequency. This variation in frequency of sound wave due to motion is called the Doppler shift (Doppler effect). In general,

                     f^{\prime}=\left(\frac{v+v_{0}}{v-v_{s}}\right) \times f

Where,

f^' - Observed frequency

f – Actual frequency

v – Velocity of sound waves

v_0 – Velocity of observer

v_s - velocity of source

When source moves away from an observer at rest (v_{0} = 0), the equation would be

                        f^{\prime}=\left(\frac{v}{v-\left(-v_{s}\right)}\right) \times f

                        f^{\prime}=\left(\frac{v}{v+v_{s}}\right) \times f

                        \frac{f^{\prime}}{f}=\left(\frac{v}{v+v_{s}}\right)

By substituting the known values, we get

            0.959=\left(\frac{343}{343+v_{s}}\right)

           0.959\left(343+v_{s}\right)=343

           0.959(343)+0.959\left(v_{s}\right)=343

           328.937+0.959 v_{s}=343

           0.959 v_{s}=343-328.937=14.063

           v_{s}=\frac{14.063}{0.959}=14.66 \mathrm{m} / \mathrm{s}

Approximately 15 m/s is the speed of the car.

3 0
3 years ago
What feature of an object does not affect air resistance?
lakkis [162]
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7 0
3 years ago
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san4es73 [151]

Answer:

The dart with the small mass will travel the farthest distance.

Explanation:

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